Maths I — Week 6: Integration Fundamentals
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Maths I — Week 6: Integration Fundamentals
The Big Idea: Differentiation breaks functions apart. Integration puts them back together. If you know the speed at every moment, integration gives you the total distance. If you know the marginal cost of each unit, integration gives you the total cost. It is the accumulation machine.
1. The Antiderivative (Indefinite Integral)
F(x) is called an antiderivative of f(x) if F′(x)=f(x).
∫f(x)dx=F(x)+C
Why +C? Differentiation erases constants (dxd(F(x)+5)=F′(x)). So when we reverse that, we must account for any constant that could have been there — hence the family of functions represented by +C.
Omitting
+C from an indefinite integral is a guaranteed mark loss. Indefinite integrals represent families of functions, not a single one.
2. Standard Integration Table
| f(x) | ∫f(x)dx |
|---|---|
| xn (n=−1) | n+1xn+1+C |
| x1 | $\ln |
| ex | ex+C |
| eax | a1eax+C |
| sinx | −cosx+C |
| cosx | sinx+C |
| sec2x | tanx+C |
| ax | lnaax+C |
3. The Fundamental Theorem of Calculus (FTC)
This is the most important theorem in calculus. It bridges differentiation and integration.
FTC Part 1 — Differentiation of an Integral (Derivative recovers the integrand)
dxd∫axf(t)dt=f(x)
Use case: Immediately resolve dxd applied to an integral whose upper limit is x.
Chain Rule Extension: If the upper limit is g(x):
dxd∫ag(x)f(t)dt=f(g(x))⋅g′(x)
FTC Part 2 — Evaluation of Definite Integrals
∫abf(x)dx=F(b)−F(a)
Use case: Evaluating any definite integral with a known antiderivative F(x).
The constant
+C cancels out in definite integrals: [F(x)+C]ab=F(b)+C−F(a)−C=F(b)−F(a).
4. Properties of Definite Integrals
| Property | Formula |
|---|---|
| Direction reversal | ∫abf=−∫baf |
| Zero width | ∫aaf=0 |
| Linearity | ∫abcf=c∫abf |
| Sum | ∫ab[f+g]=∫abf+∫abg |
| Additivity | ∫abf=∫acf+∫cbf |
| Even functions | ∫−aaf(x)dx=2∫0af(x)dx |
| Odd functions | ∫−aaf(x)dx=0 |
5. Signed Area vs. Geometric Area
The definite integral ∫abf(x)dx computes signed area:
- Regions above the x-axis contribute positively.
- Regions below the x-axis contribute negatively.
For actual (geometric) area, integrate the absolute value: ∫ab∣f(x)∣dx.
Procedure for Area Enclosed by Curve and X-axis
- Find where f(x)=0 (the roots that bound the region).
- Determine the sign of f(x) on each sub-interval.
- Integrate with appropriate sign adjustments.
Worked Example:
Area enclosed by y=x2−4 and the x-axis.
- Roots: x=±2.
- f is negative on (−2,2).
- Area =−∫−22(x2−4)dx=−[3x3−4x]−22.
- =−[(38−8)−(3−8+8)]=−[316−16]=332.
6. Pattern — Standard Anti-Differentiation
What to recognize: A polynomial or sum of standard functions without a composite inside.
Abstract Solution (Strategy)
- [Decompose]: Break the integrand into simpler standard forms.
- [Apply Table]: Integrate each term using the table above.
- [Add +C].
Worked Example:
∫(3x2+2ex−x1)dx
- Term 1: 3⋅3x3=x3.
- Term 2: 2ex.
- Term 3: −ln∣x∣.
- Result: x3+2ex−ln∣x∣+C.
7. Pattern — FTC Part 1 Applied
What to recognize: dxd applied to an integral with a variable upper bound.
Worked Example:
dxd∫0xsin(t2)dt
- By FTC Part 1 directly: sin(x2).
Chain Rule Extension Example:
dxd∫1x3etdt
- =ex3⋅3x2.
8. Common Mistakes
| Mistake | Why it happens | Correct approach |
|---|---|---|
| Forgetting +C in indefinite integrals | Treating integration like definite integrals. | Indefinite = always +C. Definite = no +C (it cancels). |
| Wrong antiderivative for 1/x | Applying power rule: x−1→0x0 (undefined). | $\int \frac{1}{x},dx = \ln |
| Signed area confusion | Just integrating without checking if f dips below x-axis. | Split the integral at roots; negate below-axis segments for geometric area. |
| Applying FTC Part 1 when lower limit isn't constant | Misidentifying which part to use. | If both limits are variable, subtract: ∫ghf=F(h)−F(g), then differentiate using Chain Rule on each. |
9. Flashcards
<Flashcard front="State FTC Part 2." back="∫[a→b] f(x)dx = F(b) - F(a), where F'(x) = f(x)." /> <Flashcard front="Why does indefinite integration need +C?" back="Differentiation destroys constants. Integration must account for any constant that might have been present — hence a family of functions." /> <Flashcard front="What is the antiderivative of 1/x?" back="ln|x| + C. The absolute value is essential — ln is not defined for negative x." /> <Flashcard front="If f is an odd function, what is ∫[-a to a] f(x)dx?" back="Zero. Odd functions have symmetric cancellation around the y-axis." /> <Flashcard front="FTC Part 1: what is d/dx ∫[0 to x] sin(t²)dt?" back="sin(x²). The derivative of an integral with variable upper limit just evaluates the integrand there." />10. Practice Targets
- Compute ∫14(3x−x2)dx.
- Find the area enclosed between y=sinx and the x-axis for x∈[0,2π].
- Apply FTC Part 1: find dxd∫1x2et2dt.
- Attempt Graded Assignment 6 Questions 1–5.
11. Connections
| Connects to | How |
|---|---|
| Week 4 — Derivatives | Integration is the reverse of differentiation. Every antiderivative formula is a derivative rule run backwards. |
| Week 7 — Advanced Integration | Substitution and Integration by Parts extend the standard table to composite functions and products. |
| Statistics I | Probability density functions (PDFs) integrate to 1 — direct application of definite integrals. |