Maths I — Week 6: Integration Fundamentals

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Maths I — Week 6: Integration Fundamentals

The Big Idea: Differentiation breaks functions apart. Integration puts them back together. If you know the speed at every moment, integration gives you the total distance. If you know the marginal cost of each unit, integration gives you the total cost. It is the accumulation machine.

1. The Antiderivative (Indefinite Integral)

F(x)F(x) is called an antiderivative of f(x)f(x) if F(x)=f(x)F'(x) = f(x).
f(x)dx=F(x)+C\int f(x)\,dx = F(x) + C
Why +C+C? Differentiation erases constants (ddx(F(x)+5)=F(x)\frac{d}{dx}(F(x) + 5) = F'(x)). So when we reverse that, we must account for any constant that could have been there — hence the family of functions represented by +C+C.
Omitting
+C+C from an indefinite integral is a guaranteed mark loss. Indefinite integrals represent families of functions, not a single one.

2. Standard Integration Table

f(x)f(x)f(x)dx\int f(x)\,dx
xnx^n (n1n \neq -1)xn+1n+1+C\dfrac{x^{n+1}}{n+1} + C
1x\frac{1}{x}$\ln
exe^xex+Ce^x + C
eaxe^{ax}1aeax+C\frac{1}{a}e^{ax} + C
sinx\sin xcosx+C-\cos x + C
cosx\cos xsinx+C\sin x + C
sec2x\sec^2 xtanx+C\tan x + C
axa^xaxlna+C\frac{a^x}{\ln a} + C

3. The Fundamental Theorem of Calculus (FTC)

This is the most important theorem in calculus. It bridges differentiation and integration.

FTC Part 1 — Differentiation of an Integral (Derivative recovers the integrand)

ddxaxf(t)dt=f(x)\frac{d}{dx}\int_a^x f(t)\,dt = f(x)
Use case: Immediately resolve ddx\frac{d}{dx} applied to an integral whose upper limit is xx.
Chain Rule Extension: If the upper limit is g(x)g(x): ddxag(x)f(t)dt=f(g(x))g(x)\frac{d}{dx}\int_a^{g(x)} f(t)\,dt = f(g(x)) \cdot g'(x)

FTC Part 2 — Evaluation of Definite Integrals

abf(x)dx=F(b)F(a)\int_a^b f(x)\,dx = F(b) - F(a)
Use case: Evaluating any definite integral with a known antiderivative F(x)F(x).
The constant
+C+C cancels out in definite integrals: [F(x)+C]ab=F(b)+CF(a)C=F(b)F(a)[F(x)+C]_a^b = F(b)+C - F(a)-C = F(b)-F(a).

4. Properties of Definite Integrals

PropertyFormula
Direction reversalabf=baf\int_a^b f = -\int_b^a f
Zero widthaaf=0\int_a^a f = 0
Linearityabcf=cabf\int_a^b cf = c\int_a^b f
Sumab[f+g]=abf+abg\int_a^b [f+g] = \int_a^b f + \int_a^b g
Additivityabf=acf+cbf\int_a^b f = \int_a^c f + \int_c^b f
Even functionsaaf(x)dx=20af(x)dx\int_{-a}^a f(x)\,dx = 2\int_0^a f(x)\,dx
Odd functionsaaf(x)dx=0\int_{-a}^a f(x)\,dx = 0

5. Signed Area vs. Geometric Area

The definite integral abf(x)dx\int_a^b f(x)\,dx computes signed area:
  • Regions above the x-axis contribute positively.
  • Regions below the x-axis contribute negatively.
For actual (geometric) area, integrate the absolute value: abf(x)dx\int_a^b |f(x)|\,dx.

Procedure for Area Enclosed by Curve and X-axis

  1. Find where f(x)=0f(x) = 0 (the roots that bound the region).
  2. Determine the sign of f(x)f(x) on each sub-interval.
  3. Integrate with appropriate sign adjustments.
Worked Example:
Area enclosed by y=x24y = x^2 - 4 and the x-axis.
  • Roots: x=±2x = \pm 2.
  • ff is negative on (2,2)(-2, 2).
  • Area =22(x24)dx=[x334x]22= -\int_{-2}^{2}(x^2-4)\,dx = -\left[\frac{x^3}{3} - 4x\right]_{-2}^{2}.
  • =[(838)(83+8)]=[16316]=323= -\left[\left(\frac{8}{3}-8\right) - \left(\frac{-8}{3}+8\right)\right] = -\left[\frac{16}{3} - 16\right] = \frac{32}{3}.

6. Pattern — Standard Anti-Differentiation

What to recognize: A polynomial or sum of standard functions without a composite inside.

Abstract Solution (Strategy)

  1. [Decompose]: Break the integrand into simpler standard forms.
  2. [Apply Table]: Integrate each term using the table above.
  3. [Add +C+C].
Worked Example:
(3x2+2ex1x)dx\int \left(3x^2 + 2e^x - \frac{1}{x}\right)\,dx
  • Term 1: 3x33=x33 \cdot \frac{x^3}{3} = x^3.
  • Term 2: 2ex2e^x.
  • Term 3: lnx-\ln|x|.
  • Result: x3+2exlnx+Cx^3 + 2e^x - \ln|x| + C.

7. Pattern — FTC Part 1 Applied

What to recognize: ddx\frac{d}{dx} applied to an integral with a variable upper bound.
Worked Example:
ddx0xsin(t2)dt\frac{d}{dx}\int_0^x \sin(t^2)\,dt
  • By FTC Part 1 directly: sin(x2)\sin(x^2).
Chain Rule Extension Example:
ddx1x3etdt\frac{d}{dx}\int_1^{x^3} e^t\,dt
  • =ex33x2= e^{x^3} \cdot 3x^2.

8. Common Mistakes

MistakeWhy it happensCorrect approach
Forgetting +C+C in indefinite integralsTreating integration like definite integrals.Indefinite = always +C+C. Definite = no +C+C (it cancels).
Wrong antiderivative for 1/x1/xApplying power rule: x1x00x^{-1} \to \frac{x^0}{0} (undefined).$\int \frac{1}{x},dx = \ln
Signed area confusionJust integrating without checking if ff dips below x-axis.Split the integral at roots; negate below-axis segments for geometric area.
Applying FTC Part 1 when lower limit isn't constantMisidentifying which part to use.If both limits are variable, subtract: ghf=F(h)F(g)\int_g^h f = F(h) - F(g), then differentiate using Chain Rule on each.

9. Flashcards

<Flashcard front="State FTC Part 2." back="∫[a→b] f(x)dx = F(b) - F(a), where F'(x) = f(x)." /> <Flashcard front="Why does indefinite integration need +C?" back="Differentiation destroys constants. Integration must account for any constant that might have been present — hence a family of functions." /> <Flashcard front="What is the antiderivative of 1/x?" back="ln|x| + C. The absolute value is essential — ln is not defined for negative x." /> <Flashcard front="If f is an odd function, what is ∫[-a to a] f(x)dx?" back="Zero. Odd functions have symmetric cancellation around the y-axis." /> <Flashcard front="FTC Part 1: what is d/dx ∫[0 to x] sin(t²)dt?" back="sin(x²). The derivative of an integral with variable upper limit just evaluates the integrand there." />

10. Practice Targets

  • Compute 14(3x2x)dx\int_1^4 \left(3\sqrt{x} - \frac{2}{x}\right)\,dx.
  • Find the area enclosed between y=sinxy = \sin x and the x-axis for x[0,2π]x \in [0, 2\pi].
  • Apply FTC Part 1: find ddx1x2et2dt\frac{d}{dx}\int_1^{x^2} e^{t^2}\,dt.
  • Attempt Graded Assignment 6 Questions 1–5.

11. Connections

Connects toHow
Week 4 — DerivativesIntegration is the reverse of differentiation. Every antiderivative formula is a derivative rule run backwards.
Week 7 — Advanced IntegrationSubstitution and Integration by Parts extend the standard table to composite functions and products.
Statistics IProbability density functions (PDFs) integrate to 1 — direct application of definite integrals.

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