Maths I — Week 7: Advanced Integration

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Maths I — Week 7: Advanced Integration

Short description. Advanced integration involves reversing the chain rule and product rule. These techniques allow us to calculate areas and accumulated quantities for complex mathematical models.

1. Core Concept

Definition: Advanced Integration is the systematic process of reducing complex products and composite functions into basic integrable forms using structural identities and algebraic maneuvers.
Intuition:
  • Substitution is the Inverse Chain Rule.
  • Integration by Parts is the Inverse Product Rule.
  • Partial Fractions is the Inverse Common Denominator.
Formula / Rule (Integration by Parts): udv=uvvdu\int u \, dv = uv - \int v \, du

2. Pattern A — The Substitution Protocol (u-substitution)

What to recognize: A composite function f(g(x))f(g(x)) where the derivative of the inner function g(x)g'(x) is also present in the integrand.

Abstract Strategy

  1. [Identification]: Identify the "inner" function g(x)g(x) whose derivative is sitting outside.
  2. [Variable Swap]: Let u=g(x)u = g(x), then du=g(x)dxdu = g'(x)\,dx.
  3. [Re-normalization]: Rewrite the entire integral in terms of uu. Solve and finally revert to xx.

Procedure

  • Step 1: Choose uu (usually the part under a power or inside a trig function).
  • Step 2: Calculate dudu and solve for dxdx if needed.
  • Step 3: Substitute and integrate using the Power Rule or Transcendental rules.
Worked Example:
Question: Compute 2x(x2+1)5dx\int 2x(x^2 + 1)^5 \, dx
  • Step 1: Let u=x2+1u = x^2 + 1.
  • Step 2: du=2xdxdu = 2x \, dx.
  • Step 3: u5du=u66+C\int u^5 \, du = \frac{u^6}{6} + C.
  • Answer: (x2+1)66+C\frac{(x^2+1)^6}{6} + C

3. Pattern B — Integration by Parts (ILATE Rule)

What to recognize: A product of two distinct types of functions (e.g., xexx \cdot e^x or xsinxx \cdot \sin x).

Abstract Strategy

  1. [Priority Check]: Determine which function is uu using the ILATE priority hierarchy:
    • I: Inverse Trig
    • L: Logarithmic
    • A: Algebraic (xnx^n)
    • T: Trigonometric
    • E: Exponential
  2. [Derivative/Integral Map]: Find dudu by differentiating uu and find vv by integrating dvdv.
  3. [Apply Identity]: Plug into uvvduuv - \int v\,du.

Procedure

  • Step 1: Assign uu and dvdv. (Algebraic usually beats Trig/Exp for uu).
  • Step 2: Compute du=udxdu = u'dx and v=dvv = \int dv.
  • Step 3: Plug in and solve the remaining integral.
Worked Example:
Question: Compute xln(x)dx\int x \cdot \ln(x) \, dx
  • Step 1: u=ln(x)u = \ln(x) (Log before Algebraic). dv=xdxdv = x \, dx.
  • Step 2: du=1xdxdu = \frac{1}{x} dx, v=x22v = \frac{x^2}{2}.
  • Step 3: x22ln(x)x221xdx\frac{x^2}{2} \ln(x) - \int \frac{x^2}{2} \cdot \frac{1}{x} \, dx.
  • Answer: x22ln(x)x24+C\frac{x^2}{2}\ln(x) - \frac{x^2}{4} + C

4. Pattern C — Partial Fraction Decomposition

What to recognize: Integrating a rational function P(x)Q(x)\frac{P(x)}{Q(x)} where degP<degQ\deg P < \deg Q.

Abstract Solution (Strategy)

  1. [Factor denominator]: Fully factor Q(x)Q(x) into linear/quadratic factors.
  2. [Set up partial fractions]: For each distinct linear factor (xr)(x - r), write a term Axr\frac{A}{x-r}. For repeated factors (xr)2(x-r)^2, write Axr+B(xr)2\frac{A}{x-r} + \frac{B}{(x-r)^2}.
  3. [Solve for constants]: Multiply both sides by Q(x)Q(x) and equate coefficients (or plug in roots).
  4. [Integrate each term]: Use 1xrdx=lnxr+C\int \frac{1}{x-r}\,dx = \ln|x-r| + C.

Procedure

  • Step 1: Verify degP<degQ\deg P < \deg Q (if not, perform polynomial long division first).
  • Step 2: Decompose the fraction.
  • Step 3: Find constants by plugging in the roots of Q(x)Q(x).
  • Step 4: Integrate each simple fraction.
Worked Example:
1(x1)(x+2)dx\int \frac{1}{(x-1)(x+2)}\,dx
  • Step 1: 1(x1)(x+2)=Ax1+Bx+2\frac{1}{(x-1)(x+2)} = \frac{A}{x-1} + \frac{B}{x+2}.
  • Step 2: Multiply: 1=A(x+2)+B(x1)1 = A(x+2) + B(x-1).
  • Step 3: At x=1x=1: 1=3A    A=1/31 = 3A \implies A = 1/3. At x=2x=-2: 1=3B    B=1/31 = -3B \implies B = -1/3.
  • Step 4: 1/3x1dx1/3x+2dx=13lnx113lnx+2+C\int \frac{1/3}{x-1}\,dx - \int \frac{1/3}{x+2}\,dx = \frac{1}{3}\ln|x-1| - \frac{1}{3}\ln|x+2| + C.
  • Result: 13lnx1x+2+C\frac{1}{3}\ln\left|\frac{x-1}{x+2}\right| + C.
Plugging in the
roots of the denominator directly into the multiplied equation is the fastest way to find constants. No systems of equations needed.

5. Definite Integration with u-Substitution (Limit Change)

When doing definite integrals with u=g(x)u = g(x), always convert the limits: abf(g(x))g(x)dx=g(a)g(b)f(u)du\int_a^b f(g(x)) g'(x)\,dx = \int_{g(a)}^{g(b)} f(u)\,du
Worked Example:
012x(x2+1)5dx\int_0^1 2x(x^2+1)^5\,dx
  • Let u=x2+1u = x^2+1. When x=0x=0, u=1u=1. When x=1x=1, u=2u=2.
  • 12u5du=[u66]12=64616=636=212\int_1^2 u^5\,du = \left[\frac{u^6}{6}\right]_1^2 = \frac{64}{6} - \frac{1}{6} = \frac{63}{6} = \frac{21}{2}.

6. Common Mistakes

MistakeWhy it happensCorrect approach
Forgetting to change limits in definite u-sub.Treating the uu integral with xx boundaries.Always calculate new u(a)u(a) and u(b)u(b) values immediately after defining uu.
Picking uu randomly in IBP.Ignoring the ILATE sequence.Follow ILATE! Picking an exponential as uu usually makes the integral harder.
Missing the +C+ C constant.Treating integrals as definitive values rather than families of functions.Indefinite integrals strictly demand the arbitrary constant CC.

7. Flashcards

<Flashcard front="What is the ILATE rule priority order?" back="Inverse Trig > Logarithmic > Algebraic > Trigonometric > Exponential." /> <Flashcard front="When do you use Partial Fraction decomposition?" back="When integrating a rational function P(x)/Q(x) where the degree of P is less than the degree of Q." /> <Flashcard front="State the Integration by Parts formula." back="∫u dv = uv - ∫v du." /> <Flashcard front="How do you handle limits in u-substitution for definite integrals?" back="Convert the limits: new lower limit = g(a), new upper limit = g(b). Don't substitute back to x." /> <Flashcard front="For partial fractions, what do you do if the numerator degree ≥ denominator degree?" back="Perform polynomial long division first to reduce to a proper fraction before decomposing." />

8. Practice Targets

  • Compute x2exdx\int x^2 e^x\,dx using the Tabular Method (repeated Integration by Parts).
  • Decompose 2x+1x2+3x+2\frac{2x+1}{x^2+3x+2} into partial fractions and integrate.
  • Evaluate 0π/2xcosxdx\int_0^{\pi/2} x\cos x\,dx using IBP.
  • Attempt Integration questions from Graded Assignment 7 (Questions 1--5).

9. Connections

Connects toHow
Week 6 — Integration FundamentalsAdvanced integration extends the standard table to products and composites.
Week 5 — Partial Fractions (Polynomials)The denominator factoring in Partial Fractions uses the polynomial skills from Week 4.
Physics / EngineeringSubstitution handles variable density and non-uniform work calculations.

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