Quiz 2
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Quantifier Manipulation

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Quantifier Manipulation

Swapping Quantifiers

  • ∀x∃yP(x,y)\forall x \exists y P(x,y) is NOT equivalent to ∃y∀xP(x,y)\exists y \forall x P(x,y)
  • ∀x∀yP(x,y)≡∀y∀xP(x,y)\forall x \forall y P(x,y) \equiv \forall y \forall x P(x,y)
  • ∃x∃yP(x,y)≡∃y∃xP(x,y)\exists x \exists y P(x,y) \equiv \exists y \exists x P(x,y) Join Discord PreviousPredicate LogicNextProof Techniques
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