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Week 9: Integration, Areas & the Fundamental Theorem
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Week 9: Integration, Areas & the Fundamental Theorem
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2026-09-12
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Mathematics I — Week 9: Integration, Areas & the Fundamental Theorem
IITM’s Week 9 covers integration of a function of one variable, computing areas, area under a curve, and the relationship between derivatives and integrals.
TL;DR
Week 8 asked:
How fast is something changing?
Week 9 asks:
How much change has accumulated?
The central object is the integral.
Two core ideas:
and
The key bridge is the Fundamental Theorem of Calculus, which links derivatives and integrals.
1. Antiderivative intuition
Suppose:
Then F is called an antiderivative of f.
Example:
Then:
So an antiderivative of:
is:
2. Indefinite integral
We write:
for the family of antiderivatives of f.
If:
then:
where:
is an arbitrary constant.
3. Why the constant C appears
Because derivatives of constants vanish.
For example:
but also:
and:
So all functions:
have derivative:
Hence:
4. Basic integration notation
In:
- ∫ = integral sign
- f(x) = integrand
- dx = variable of integration
The integral sign is historically a stretched form of the letter S, referring to a sum.
That becomes intuitive when we discuss area.
5. Power rule for integration
For:
Compare with differentiation:
Integration roughly reverses the power rule.
6. Examples
∫x2dx=3x3+Cbecause:
Similarly:
7. Integrating constants
∫cdx=cx+C.Why?
Because:
Example:
8. Constant multiple rule
∫cf(x)dx=c∫f(x)dxExample:
so:
9. Sum and difference rules
∫[f(x)+g(x)]dx=∫f(x)dx+∫g(x)dxand:
10. Polynomial integration
Example:
Integrate term by term:
Simplify:
11. Check your answer by differentiating
If you think:
differentiate:
If:
your integration is correct.
This is one of the best self-checks in calculus.
12. Special case: ∫x1dx
The ordinary power rule fails for:
because it would require division by:
Instead:
for:
Why absolute value?
Because:
on both positive and negative domains.
13. Exponential integrals
Because:
we have:
For general base:
for:
14. Integration as accumulated area
Now the second interpretation.
Suppose:
on:
The area under:
from x=a to x=b is represented by:
This is a definite integral.
15. Definite integral notation
∫abf(x)dxwhere:
- a = lower limit
- b = upper limit
- f(x) = integrand
Unlike the indefinite integral, the definite integral evaluates to a number.
16. Why integration is related to summation
Imagine dividing:
into many thin rectangles.
For each rectangle:
Then add all rectangle areas:
As the rectangles become thinner:
the approximation becomes exact.
This limiting sum gives:
This is the conceptual origin of integration.
17. Riemann sum intuition
A typical approximation is:
As:
the width:
Then:
under appropriate conditions.
This ties Week 7 limits directly into Week 9 integration.
18. Fundamental Theorem of Calculus
This is one of the most important results in calculus.
If:
then:
This means we do not usually need to compute infinite rectangle sums manually.
Instead:
- find an antiderivative
- evaluate at upper bound
- subtract value at lower bound
19. Example
Compute:
An antiderivative is:
So:
Evaluate:
Therefore:
20. Bracket notation
We often write:
to mean:
So:
means:
21. No +C in a definite integral
When evaluating:
we do not need to write:
Why?
Suppose antiderivative is:
Then:
equals:
The constants cancel.
22. Example: polynomial definite integral
Evaluate:
Antiderivative:
Thus:
At 3:
At 1:
Therefore:
23. Geometric verification
For:
between:
and:
the graph forms a trapezoid.
Heights:
and:
Width:
Trapezoid area:
Matches the integral.
24. Signed area
This is crucial:
A definite integral gives signed area, not always ordinary geometric area.
If:
contribution is positive.
If:
contribution is negative.
So regions below the x-axis subtract.
25. Example below the axis
Consider:
on:
Then:
Geometric area is:
but definite integral is:
26. Net area vs total area
Suppose a graph crosses the x-axis.
Then:
gives net signed area.
If the question asks for actual geometric area, you need:
or split at the zeros.
27. Example: signed cancellation
Take:
on:
Then:
Why?
Area below axis from −1 to 0 is:
Area above axis from 0 to 1 is:
They cancel.
But total geometric area is:
28. Symmetry shortcut: odd functions
If:
then f is odd.
Over symmetric limits:
we get:
Example:
Thus:
29. Symmetry shortcut: even functions
If:
then f is even.
Then:
Example:
30. Basic properties of definite integrals
Same limits
∫aaf(x)dx=0Reversing limits
∫abf(x)dx=−∫baf(x)dxSplitting interval
For any c between a and b:
31. Linearity of definite integrals
∫ab[αf(x)+βg(x)]dx=α∫abf(x)dx+β∫abg(x)dxThis is extremely useful.
32. Area between two curves
Suppose:
on:
Then the area between the curves is:
Think:
33. Example: area between curves
Find the area between:
and:
from:
to:
On this interval:
So area:
Integrate:
Thus:
34. Find intersection points first
If bounds are not given, solve:
to find where curves intersect.
Example:
Then:
So:
These become integration limits.
35. Antiderivative families
Suppose:
Then:
If we additionally know:
then:
So:
Thus:
An initial condition picks one member from the antiderivative family.
36. Recovering position from velocity
Suppose velocity:
Then displacement from:
to:
is:
This gives the physical meaning of integration as accumulation.
37. Displacement vs distance
If velocity becomes negative, then:
gives net displacement.
Total distance traveled requires accounting for magnitude:
Exactly analogous to signed area vs geometric area.
38. Fundamental Theorem — deeper intuition
Suppose:
This defines accumulated area from a to x.
Then, under suitable conditions:
So:
the instantaneous rate at which accumulated area changes is the current height of the function.
That is the deeper reason differentiation and integration are inverses.
39. Why does A′(x)=f(x) make sense?
Increase x by a tiny amount:
The new area added is approximately a thin rectangle:
Thus:
As:
we get:
This is one of the nicest intuitions in calculus.
40. Substitution intuition
Sometimes an integral contains a nested expression.
Example:
Notice:
Let:
Then:
So the integral becomes:
Thus:
Substitute back:
This is u-substitution, essentially the reverse chain rule.
41. Reverse chain-rule mental model
Differentiation:
Integration reverses that pattern:
This is the cleanest way to understand substitution.
42. Example
Evaluate:
Let:
Then:
So:
Therefore:
43. Another example
∫x2+12xdx.Let:
Then:
So:
Since:
we get:
44. Definite integral with substitution
Consider:
Let:
When:
When:
So:
Then:
45. Average value of a function
The average value of:
on:
is:
This generalizes the ordinary idea:
46. Example: average value
For:
on:
We know:
Therefore:
which matches the intuitive average height.
Common mistake: forgetting
+C
For:
you generally need:
For definite integrals, you do not.
Common mistake: integrating powers incorrectly
Wrong:
That is differentiation-style thinking.
Correct:
Integration:
add 1 to exponent, then divide by new exponent.
Common mistake: power rule for
x−1
Do not use:
when:
Instead:
Common mistake: integral equals geometric area
Not always.
is signed.
If f crosses below the axis, negative parts subtract.
If question says total area, split intervals or use absolute values.
Common mistake: upper minus lower backwards
Correct:
not:
Common mistake: integrating products termwise
There is no general rule:
That is false.
Products may require:
- substitution
- other methods later
So recognize structure instead of inventing a product-integration rule.
Common mistake: confusing derivative and integral symbols
Derivative:
asks for rate of change.
Integral:
asks for antiderivative/accumulation.
They are linked but not the same operation.
54. Derivative ↔ integral table
| Differentiation | Integration |
|---|---|
| local change | accumulated change |
| tangent slope | signed area |
| reduces powers | increases powers |
| F→F′ | f→F |
| derivative of constant = 0 | integral introduces +C |
| chain rule | substitution reverses chain rule |
This table captures most of the conceptual bridge.
55. Integration formula sheet
Power rule
For n=−1:
Constant
∫cdx=cx+CReciprocal
∫x1dx=ln∣x∣+CExponential
∫exdx=ex+CGeneral exponential
∫axdx=lnaax+C56. Definite integral formula sheet
Fundamental theorem
If:
then:
Reverse bounds
∫abf=−∫bafSplit intervals
∫abf=∫acf+∫cbfArea between curves
A=∫ab(top−bottom)dx57. Full worked example
Evaluate:
Antiderivative:
Therefore:
At:
At:
So:
58. Full area example crossing the axis
Find total area between:
and the x-axis from:
to:
The function changes sign at:
So total area:
First:
Magnitude:
Second:
Therefore total geometric area:
59. Weeks 7–9 as one calculus story
textWeek 7 LIMITS "What happens as we approach?" ↓ Week 8 DERIVATIVE "How fast is it changing now?" ↓ Week 9 INTEGRAL "How much has accumulated?"
And the Fundamental Theorem says:
That is the central conceptual payoff of the calculus portion so far.
60. What you should actually master
By the end of Week 9, you should be able to:
- Explain what an antiderivative is.
- Understand why indefinite integrals include +C.
- Apply the integration power rule.
- Integrate polynomials.
- Handle: ∫x1dx.
- Integrate basic exponentials.
- Interpret definite integrals as signed accumulation.
- Use: F(b)−F(a).
- Distinguish signed area from geometric area.
- Split integrals at zeros/intersections.
- Compute area between two simple curves.
- Understand the Fundamental Theorem of Calculus.
- Recognize basic substitution as the reverse chain rule.
- Recover a function from its derivative plus an initial condition.
- Interpret integrals as displacement/accumulation.
If those are comfortable, Week 9 is under control.
Quick Recall & Flashcards
Test your active recall before proceeding to practice problems. Format:
Question :: Answer.- Fundamental Theorem of Calculus (Part 1) :: dxd[∫axf(t)dt]=f(x)
- Fundamental Theorem of Calculus (Part 2) :: ∫abf(x)dx=F(b)−F(a), where F′(x)=f(x)
- Power rule for integration ∫xndx (n=−1) :: n+1xn+1+C
- Indefinite integral ∫x1dx :: ln∣x∣+C
- Indefinite integral ∫ekxdx :: k1ekx+C
- Geometric meaning of ∫abf(x)dx :: Net signed area between curve y=f(x) and x-axis
- u-substitution is the integral counterpart of :: The Chain Rule in differentiation
Practice & Self-Check
Attempt these diagnostic questions to verify your operational understanding.
1
Question 1
Evaluate the definite integral: ∫02(3x2−4x+1)dx.
NAT
3 Unit Assessment
2
Question 2
What is the derivative with respect to x of g(x)=∫1x1+t4dt?
MCQ
3 Unit Assessment
A. 1+x4
B. 21+x44x3
C. 1+x4−2
D. 1+x4