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Maths I — Week 8: Linear Algebra
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Maths I — Week 8: Linear Algebra
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Maths I — Week 8: Linear Algebra
Short description. Linear Algebra is the mathematics of organized data. Matrices allow us to solve complex systems of equations efficiently by treating entire sets of numbers as single algebraic units.
1. Core Concept
Definition: A Matrix is a rectangular array of numbers arranged in m rows and n columns. Matrix algebra provides a deterministic framework for transformations and solving systems of linear equations.
Intuition: Imagine a matrix as a spreadsheet that can be multiplied by other spreadsheets. It represents a "transformation" of space—rotating, scaling, or flipping vectors.
Formula / Rule:
Am×n⋅Bn×p=Cm×p
where the element cij is the dot product of the i-th row of A and the j-th column of B.
Important
Commutativity Fail: Unlike scalar multiplication, AB=BA in most cases. The order of multiplication is structurally sacred.
2. Pattern A — Matrix Multiplication
What to recognize: A request to find the product of two arrays A and B.
Abstract Solution (Strategy)
- [Dimension Audit]: Verify if the number of columns in A exactly matches the number of rows in B.
- [Dot Product Rule]: Each entry cij is the sum of products of corresponding elements from Row i of A and Column j of B.
- [Watch for]: Inadvertently swapping the order or incorrectly adding instead of multiplying.
Procedure
- Step 1: Check dimensions (m×n and n×p). The outer numbers (m,p) define the result size.
- Step 2: For each coordinate (i,j) in the result, multiply Row i of A with Column j of B element-wise and sum them.
- Step 3: Repeat until the result matrix is saturated.
Worked Example:
Question: Find AB for A=[1324] and B=[5768].
- Step 1: 2×2 times 2×2 = 2×2 result.
- Step 2: Top-Left coordinate (1,1)=(1⋅5)+(2⋅7)=5+14=19.
- Step 3: Fill other coordinates similarly.
- Answer: [19432250]
3. Pattern B — 2×2 Matrix Inversion
What to recognize: A question asking for A−1 where A is a square 2×2 matrix.
Abstract Solution (Strategy)
- [Determinant Check]: Calculate Delta=ad−bc. If Delta=0, the inverse does not exist (Matrix is singular).
- [Adjugate Swap]: Swap the main diagonal elements (a↔d) and negate the off-diagonal elements (−b,−c).
- [Scalar Scaling]: Multiply the resulting adjugate matrix by Δ1.
Procedure
- Step 1: Compute D=(m11⋅m22)−(m12⋅m21).
- Step 2: Rearrange: [acbd]→[d−c−ba].
- Step 3: Multiply by 1/D and simplify.
Worked Example:
Question: Inverse of [2513].
- Step 1: det=(2⋅3)−(1⋅5)=1.
- Step 2: Swap/Negate →[3−5−12].
- Step 3: 11⋅[3−5−12].
- Answer: [3−5−12]
4. Common Mistakes
| Mistake | Why it happens | Correct approach |
|---|---|---|
| Multiplying matrices of incompatible sizes. | Ignoring the dimension audit. | Always check if Col Count of A = Row Count of B. |
| Forgetting to divide by the determinant in inversions. | Skipping the final scalar scaling step. | The inverse is ONLY the adjugate IF the determinant is exactly 1. |
| Assuming AB=BA. | Applying scalar habits to matrix algebra. | The order is fundamental. (AB)T=BTAT. |
5. Flashcards
<Flashcard front="What is the condition for a matrix to be 'singular'?" back="A matrix is singular if its determinant is exactly zero, meaning it cannot be inverted." /> <Flashcard front="How do you compute the Transpose of a matrix?" back="Swap rows for columns: the element at (i, j) moves to (j, i)." /> <Flashcard front="State the Identity Matrix property for multiplication." back="AI = IA = A for any square matrix A." />6. Practice Targets
- Attempt Maths I Graded Assignment 8.
- Calculate the determinant of a 3×3 matrix using cofactor expansion on the 1st row.
- Solve Ax=b for 2×2 using x=A−1b.
7. Connections
| Connects to | How |
|---|---|
| Week 2 — Polynomials | Solving systems of linear equations is the foundational step for partial fraction decomposition and curve fitting. |
| Data Science Core | Matrices are the primary data structure for all machine learning models (tensors). |