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Jan 2026 - Mathematics I - Mock 6 Week 5-8

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Mock 6 (Week 5-8)

Course: Jan 2026 - Mathematics I
Mock 6 (Week 5-8)

Introduction

**Use the following information for questions 7-9: ** Consider the function defined as follows with p,q,rRp,q,r \in \mathbb{R}:
f(x)={pex4x+3if x < 0 q5if x = 0rsin(x)+9cos(x)ifx > 0f(x) = \begin{cases} pe^{x}-4x+ 3 & \text{if x < 0 } \\ q - 5 & \text{if x = 0}\\ rsin(x) + 9cos(x) & \text{ifx > 0}\\ \end{cases}
Use the following information for questions 10-11:
Suppose ff is a real valued function defined on domain DD. let f(x+y)=f(x)f(y)f(x+y) = f(x)f(y) for all x,yDx,y \in D and f(1)=5f(1)= 5, f(0)=3f'(0) = 3.
Use the following information for questions 12-14: Consider a sequence {an}\{a_n\} defined as
an={3nn27+nwhen n is odd5n24n+16n+2n2when nis even a_n = \begin{cases} \frac{3n - \lfloor{\frac{n}{2}}\rfloor}{7+n} & \text{when n is odd} \\ \frac{5n^2-4n+1}{6n+2n^2} & \text{when nis even } \end{cases}
where x\lfloor {x} \rfloor is the greatest integer that is less than or equal to a real number xx

Question 1

Simplify the expression (axay)(x+yz).(ayaz)(y+zx).(azax)(z+xy)(\frac{a^x}{a^y})^{(x+y-z)}.(\frac{a^y}{a^z})^{(y+z-x)}.(\frac{a^z}{a^x})^{(z+x-y)}
  • ax+y+za^{x+y+z}
  • ax2+y2+z2xyyzzxa^{x^2+y^2+z^2-xy-yz-zx}
  • 1
  • aa
Feedback/Explanation: 1
Accepted Answers:
1

Question 2

Which of the following statements are correct?
  • The functions f(x)=ln(x)f(x) = -\sqrt{ln(x)} and g(x)=ex2g(x) = e^{x^2} are inverses to each other.
  • The domain of the real-valued function f(x)=ex28x1f(x) = \sqrt{e^{x^2-8x} - 1} is (,0][8,)(-\infty,0] \cup [8,\infty).
  • The line x=3x=3 is a vertical asymptote of the function f(x)=ln(x2+5x24)f(x) = ln(x^2+5x-24).
  • ff may be continuous at the point x=ax=a even if ff is not differentiable at a point x=ax= a.
Feedback/Explanation: The domain of the real-valued function f(x)=ex28x1f(x) = \sqrt{e^{x^2-8x} - 1} is (,0][8,)(-\infty,0] \cup [8,\infty).
The line x=3x=3 is a vertical asymptote of the function f(x)=ln(x2+5x24)f(x) = ln(x^2+5x-24).
ff may be continuous at the point x=ax=a even if ff is not differentiable at a point x=ax= a.
Accepted Answers:
The domain of the real-valued function f(x)=ex28x1f(x) = \sqrt{e^{x^2-8x} - 1} is (,0][8,)(-\infty,0] \cup [8,\infty).
The line x=3x=3 is a vertical asymptote of the function f(x)=ln(x2+5x24)f(x) = ln(x^2+5x-24).
ff may be continuous at the point x=ax=a even if ff is not differentiable at a point x=ax= a.

Question 3

Suppose f(x)=x+5x3f(x) = \frac{x+5}{x-3} and g(x)=x21g(x) = \sqrt{x^2 - 1} are functions on their respective domains. Which of the following statements are correct?
  • The domain of the composite function (fg)(x)(f \circ g)(x) is (,10)(10,1][1,10)(10,)(-\infty,-\sqrt{10}) \cup (-\sqrt{10},-1] \cup [1,\sqrt{10}) \cup (\sqrt{10},\infty).
  • The domain of the composite function (fg)(x)(f \circ g)(x) is R{10,10}\mathbb{R} \setminus \{-\sqrt{10},\sqrt{10}\}.
  • (fg)(x)=x21+5x213(f \circ g)(x) = \frac{\sqrt{x^2-1}+5}{\sqrt{x^2-1}-3}.
  • (gf)(x)=4x+1x3(g \circ f)(x) = \frac{4\sqrt{x+1}}{|x-3|}.
Feedback/Explanation: The domain of the composite function (fg)(x)(f \circ g)(x) is (,10)(10,1][1,10)(10,)(-\infty,-\sqrt{10}) \cup (-\sqrt{10},-1] \cup [1,\sqrt{10}) \cup (\sqrt{10},\infty).
(fg)(x)=x21+5x213(f \circ g)(x) = \frac{\sqrt{x^2-1}+5}{\sqrt{x^2-1}-3}.
(gf)(x)=4x+1x3(g \circ f)(x) = \frac{4\sqrt{x+1}}{|x-3|}.
Accepted Answers:
The domain of the composite function (fg)(x)(f \circ g)(x) is (,10)(10,1][1,10)(10,)(-\infty,-\sqrt{10}) \cup (-\sqrt{10},-1] \cup [1,\sqrt{10}) \cup (\sqrt{10},\infty).
(fg)(x)=x21+5x213(f \circ g)(x) = \frac{\sqrt{x^2-1}+5}{\sqrt{x^2-1}-3}.
(gf)(x)=4x+1x3(g \circ f)(x) = \frac{4\sqrt{x+1}}{|x-3|}.

Question 4

Consider a sequence {ana_n} defined as an=an1+an22a_n = \frac{a_{n-1}+ a_{n-2}}{2} for all n3n \geq 3 and a1=0,a2=1a_1 = 0, a_2 = 1. Which of the following statements are correct?
  • The sequence {an}\{a_n\} is not convergent.
  • limnan=23\displaystyle \lim\limits_{n \to \infty} a_n = \frac{2}{3}.
  • i=3nai=a2+an12+i=3n2ai\displaystyle \sum_{i = 3}^{n} a_i = \frac{a_2 + a_{n-1}}{2} + \displaystyle \sum_{i = 3}^{n-2} a_i.
  • i=3nai=an12+i=2n2ai\displaystyle \sum_{i = 3}^{n} a_i = \frac{a_{n-1}}{2} + \displaystyle \sum_{i = 2}^{n-2} a_i.
Feedback/Explanation: limnan=23\displaystyle \lim\limits_{n \to \infty} a_n = \frac{2}{3}.
i=3nai=an12+i=2n2ai\displaystyle \sum_{i = 3}^{n} a_i = \frac{a_{n-1}}{2} + \displaystyle \sum_{i = 2}^{n-2} a_i.
Accepted Answers:
limnan=23\displaystyle \lim\limits_{n \to \infty} a_n = \frac{2}{3}.
i=3nai=an12+i=2n2ai\displaystyle \sum_{i = 3}^{n} a_i = \frac{a_{n-1}}{2} + \displaystyle \sum_{i = 2}^{n-2} a_i.

Question 5

Stock price (yy) (in ) for a motor cycle company (A)(A) is predicted by the equation                    y=7log2(x+a)+35,y= -7log_{2}(x+a) + 35,
where xx represents the number of months since January of the year 2022 (note: for January, consider xx= 0) and aNa \in \mathbb{N}. If the stock price of the company goes to zero in November of the year 2022, following the same trend, then find the value of aa.
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 22
Accepted Answers:
(Type: Numeric) 22

Question 6

Ravi borrowed 3,000 and 12,000 from his friends Vinay and Bhumi respectively. Vinay lent the money at 7 percent simple interest per annum for 4 years and Bhumi lent the money at 10 percent compound interest per annum for xx years. The compound interest which Bhumi received after xx years is thrice the value of the simple interest which Vinay received after 4 years. What is the value of xx? [Note: Simple interest = PTR100\frac{PTR}{100} and Compound Interest = P(1+R100)TPP(1+ \frac{R}{100})^T - P, where PP is the principle amount, TT is time (in years) and RR is the interest rate per annum, i.e., if x%x \% is the interest rate per annum then R=xR=x]
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 2
Accepted Answers:
(Type: Numeric) 2

Question 7

If the limit exists at x=0x=0 for the given function f(x)f(x), then what will be the value of pp?
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 6
Accepted Answers:
(Type: Numeric) 6

Question 8

If ff is continuous at x=0x=0, then find the value of q2\frac{q}{2}.
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 7
Accepted Answers:
(Type: Numeric) 7

Question 9

If ff is differentiable everywhere, then find the value of rr.
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 2
Accepted Answers:
(Type: Numeric) 2

Question 10

What is the value of f(0)f(0)?
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 1
Accepted Answers:
(Type: Numeric) 1

Question 11

What is the value of f(1)f'(1)?
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 15
Accepted Answers:
(Type: Numeric) 15

Question 12

Which of the following statements are correct?
  • If nn is odd, then n2=n12\lfloor{\frac{n}{2}}\rfloor = \frac{n-1}{2}.
  • If nn is even, then n2=n2+1\lfloor{\frac{n}{2}}\rfloor = \frac{n}{2}+1.
  • If nn is odd, then n2=n+12\lfloor{\frac{n}{2}}\rfloor= \frac{n+1}{2}.
  • If nn is even, then n2=n2\lfloor{\frac{n}{2}}\rfloor = \frac{n}{2}.
Feedback/Explanation: If nn is odd, then n2=n12\lfloor{\frac{n}{2}}\rfloor = \frac{n-1}{2}.
If nn is even, then n2=n2\lfloor{\frac{n}{2}}\rfloor = \frac{n}{2}.
Accepted Answers:
If nn is odd, then n2=n12\lfloor{\frac{n}{2}}\rfloor = \frac{n-1}{2}.
If nn is even, then n2=n2\lfloor{\frac{n}{2}}\rfloor = \frac{n}{2}.

Question 13

Find the limit of the sequence {4an}\{4a_n\}.
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 10
Accepted Answers:
(Type: Numeric) 10

Question 14

Find the limit of the sequence {bn}\{b_n\} defined as bn=4an210anb_n= 4a_n^2 - 10a_n.
Your Answer: (Not answered)
Feedback/Explanation: (Type: Numeric) 0
Accepted Answers:
(Type: Numeric) 0

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