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Jan 2026 - Python - Week 6 - Collections 3 - Graded

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Jan 2026 - Python - Week 6 - Collections 3 - Graded

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Graded Assignment

Course: Jan 2026 - Python

Collections 3 - Graded

Submission deadline has passed for this assignment

Due Mar 25, 2026 at 11:59 PM IST

Instructions

Use "Test Run" to verify your code with public test cases.

Press "Submit" to have your assignment evaluated.

You can submit your assignment multiple times up until the deadline.

Make sure to submit your final code by the deadline to receive your score.

Summary

100 out of100

Score

Public Tests

3/3 Passed

Submitted on Mar 25, 2026 at 2:33 PM IST

Private Tests

3/3 Passed

Submitted on Mar 25, 2026 at 2:33 PM IST

**Change in eligibility criteria to write oppe2 exam: A5>=40/100 AND A6>=40/100 AND A7>=40/100 AND A8>=40/100. and becoming eligible to give the end term exam.

Element present in exactly one of the two lists**

Given two lists, return a list containing the items that are present in either list but not in both.

Example


>>> in_exactly_one([1, 2, 3], [3, 4, 5])
{1, 2, 4, 5}

Template Code(Click to Expand)



def in_exactly_one(l1: list, l2: list) -> set:
    '''
    Given two lists, return a list containing the items
    that are present in either list but not in both.

    Arguments:
    l1: list - the first list
    l2: list - the second list

    Return:
    set - a set containing the items present in either list 1 or list 2 but not in both

    Example:
    >>> in_exactly_one([1, 2, 3], [3, 4, 5])
    {1, 2, 4, 5}
    '''
    ...

NOTE: You can use the below tools for working out and debugging. Click to open them in new tab.

PythonTutor | Starboard Notebook | Pyodide Terminal

Public Tests ( 3/3 )

Case 1

Input:


text
is_equal(
    in_exactly_one([1, 2, 3], [3, 4, 5]), {1, 2, 4, 5}
)

Expected Output:


text
{1, 2, 4, 5}

Actual Output:


text
{1, 2, 4, 5}

Case 2

Input:


text
is_equal(
    in_exactly_one(
        ['apple', 'ball', 'cat'],
        ['ball', 'cat', 'dog']
    ),
    {'apple', 'dog'}
)

Expected Output:


text
{'apple', 'dog'}

Actual Output:


text
{'apple', 'dog'}

Case 3

Input:


text
is_equal(
    in_exactly_one(
        list(range(1,10)),
        list(range(5,15))
    ),
    {*range(1,5),*range(10,15)}
)

Expected Output:


text
{1, 10, 11, 12, 13, 14, 2, 3, 4}

Actual Output:


text
{1, 10, 11, 12, 13, 14, 2, 3, 4}

Private Tests ( 3/3 )

Case 1

Input:


text
is_equal(
    in_exactly_one(
        [55, 62, 12, 22],
        [21, 35, 45]
    ),
    {35, 12, 45, 21, 22, 55, 62}
)

Expected Output:


text
{12, 21, 22, 35, 45, 55, 62}

Actual Output:


text
{12, 21, 22, 35, 45, 55, 62}

Case 2

Input:


text
is_equal(
    in_exactly_one(
        ['apple', 'ball', 'cat'],
        ['apple', 'ball', 'cat']
    ),
    set()
)

Expected Output:


text
{}

Actual Output:


text
{}

Case 3

Input:


text
is_equal(
    in_exactly_one(
        list(range(100,111)),
        list(range(102,105))
    ),
    {100,101,*range(105,111)}
)

Expected Output:


text
{100, 101, 105, 106, 107, 108, 109, 110}

Actual Output:


text
{100, 101, 105, 106, 107, 108, 109, 110}

💻 IITM Official Solution


python

def in_exactly_one(l1: list, l2: list) -> set:
    '''
    Given two lists, return a list containing the items
    that are present in either list but not in both.

    Arguments:
    l1: list - the first list
    l2: list - the second list

    Return:
    set - a set containing the items present in either list 1 or list 2 but not in both

    Example:
    >>> in_exactly_one([1, 2, 3], [3, 4, 5])
    {1, 2, 4, 5}
    '''

    return set(l1) ^ set(l2)

💻 My Submitted Code


python

def in_exactly_one(l1: list, l2: list) -> set:
    '''
    Given two lists, return a list containing the items
    that are present in either list but not in both.

    Arguments:
    l1: list - the first list
    l2: list - the second list

    Return:
    set - a set containing the items present in either list 1 or list 2 but not in both

    Example:
    >>> in_exactly_one([1, 2, 3], [3, 4, 5])
    {1, 2, 4, 5}
    '''
    ...

    return set(l1) ^ set(l2)