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Jan 2026 - Python - Week 8 - GrPA 2

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Jan 2026 - Python - Week 8 - GrPA 2

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Graded Assignment

Course: Jan 2026 - Python

GrPA 2

Submission deadline has passed for this assignment

Due Apr 08, 2026 at 11:59 PM IST

Instructions

Use "Test Run" to verify your code with public test cases.

Press "Submit" to have your assignment evaluated.

You can submit your assignment multiple times up until the deadline.

Make sure to submit your final code by the deadline to receive your score.

Summary

100 out of100

Score

Public Tests

3/3 Passed

Submitted on Apr 08, 2026 at 5:46 AM IST

Private Tests

5/5 Passed

Submitted on Apr 08, 2026 at 5:46 AM IST

**Change in eligibility criteria to write oppe2 exam: A5>=40/100 AND A6>=40/100 AND A7>=40/100 AND A8>=40/100. and becoming eligible to give the end term exam. ** You are given two non-empty text files file1 and file2 that have

f_1

and

f_2

lines respectively. Each file is a collection of ten-digit phone numbers, one number per line. It is also known that

0 < f_1 \leq f_2

The following relations are defined on these two files:

Subset: file1 is a subset of file2 if the phone number in the $i^{th}$ line of file1 is equal to the number in the $i^{th}$ line of file2, for $1 \leq i \leq f_1$ , and $f_1 < f_2$ .
Equal: file1 is equal to file2 if the phone number in the $i^{th}$ line of file1 is equal to the number in the $i^{th}$ line of file2 for $1 \leq i \leq f_1$ , and $f_1 = f_2$ .

Write a function named relation that accepts these two text files as arguments. It should return the string Subset if file1 is a subset of file2. It should return Equal if file1 is equal to file2. If both these conditions are not satisfied, it should return the string No Relation.

(1) file1 and file2 are string variables that hold the names of the two files. For example, in the first test case, it is file1 = 'public_1_1.txt' and file2 = 'public_1_2.txt'.

(2) You do not have to accept input from the console or print the output to the console. You just have to write the function definition.

(3) The strings '9876543210' and '9876543210\n' are not the same, though the phone numbers are the same. So, strip the strings of all new lines using the strip method before checking for equality of two lines across the files.

Public Tests ( 3/3 )

Case 1

Input:


text
100
public_1_1.txt
public_1_2.txt

Expected Output:


text
Subset

Actual Output:


text
Subset

Case 2

Input:


text
300
public_2_1.txt
public_2_2.txt

Expected Output:


text
No Relation

Actual Output:


text
No Relation

Case 3

Input:


text
500
public_3_1.txt
public_3_2.txt

Expected Output:


text
Equal

Actual Output:


text
Equal

Private Tests ( 5/5 )

Case 1

Input:


text
700
private_1_1.txt
private_1_2.txt

Case 2

Input:


text
900
private_2_1.txt
private_2_2.txt

Case 3

Input:


text
1100
private_3_1.txt
private_3_2.txt

Case 4

Input:


text
1300
private_4_1.txt
private_4_2.txt

Case 5

Input:


text
2341
private_5_1.txt
private_5_2.txt

💻 IITM Official Solution


python
def relation(file1, file2):
    f1 = open(file1, 'r')
    L1 = f1.readlines()
    for i in range(len(L1)):
        L1[i] = L1[i].strip()
    f1.close()

    f2 = open(file2, 'r')
    L2 = f2.readlines()
    for i in range(len(L2)):
        L2[i] = L2[i].strip()
    f2.close()

    if L1 == L2:
        return 'Equal'

    for i in range(len(L1)):
        if L1[i] != L2[i]:
            return 'No Relation'
    return 'Subset'

💻 My Submitted Code


python
def relation(file1, file2):
    f1 = open(file1, 'r')
    f2 = open(file2, 'r')

    # Read all lines into lists for easier comparison
    lines1 = [line.strip() for line in f1.readlines()]
    lines2 = [line.strip() for line in f2.readlines()]

    f1.close()
    f2.close()

    count1 = len(lines1)
    count2 = len(lines2)

    # Check if lines in file1 match the corresponding lines in file2
    # The constraint says count1 <= count2
    is_match = True
    for i in range(count1):
        if lines1[i] != lines2[i]:
            is_match = False
            break

    if is_match:
        if count1 == count2:
            return 'Equal'
        else:
            return 'Subset'
    else:
        return 'No Relation'