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jan-2026-python-week-7-collections-4

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Collections 4

Course: Jan 2026 - Python

Collections 4

Submission deadline has passed for this assignment

Due Apr 01, 2026 at 11:59 PM IST

Instructions

Use "Test Run" to verify your code with public test cases.

Press "Submit" to have your assignment evaluated.

You can submit your assignment multiple times up until the deadline.

Make sure to submit your final code by the deadline to receive your score.

Summary

100 out of100

Score

Public Tests

3/3 Passed

Submitted on Apr 01, 2026 at 3:50 AM IST

Private Tests

2/2 Passed

Submitted on Apr 01, 2026 at 3:50 AM IST

**Change in eligibility criteria to write oppe2 exam: A5>=40/100 AND A6>=40/100 AND A7>=40/100 AND A8>=40/100. and becoming eligible to give the end term exam.

Find final position in 2d given initial position and velocity**

Given an initial position of a point moving in a 2d cartesian plane with a constant velocity, find the the final position of the point after a given time in two dimensions.

Hint: final position = intial position + velocity * time

Template Code(Click to Expand)



def final_position(pos: tuple, vel: tuple, time:int) -> tuple:
    '''
    Given an initial position of a point moving in a cartesian plane with a constant velocity,
    find the the final position of the point after a given time.

    Hint: final position = intial position + velocity * time

    Args:
        pos - tuple[int]: A tuple representing the position vector (x1, y1).
        vel - tuple[int]: A tuple representing the velocity vector (vx, vy).
        time - int: time of movement.

    Returns:
        tuple[int]: A tuple representing the displacement (dx, dy).
    '''
    ...

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PythonTutor | Starboard Notebook | Pyodide Terminal

Public Tests ( 3/3 )

Case 1

Input:


text
is_equal(final_position((1,1), (2,2), 3), (7,7))

Case 1

Expected Output:


text
(7, 7)

Case 1

Actual Output:


text
(7, 7)

Case 2

Input:


text
is_equal(final_position((1,2), (2,1), 3), (7,5))

Case 2

Expected Output:


text
(7, 5)

Case 2

Actual Output:


text
(7, 5)

Case 3

Input:


text
is_equal(final_position((1,1), (1,1), 2), (3,3))

Case 3

Expected Output:


text
(3, 3)

Case 3

Actual Output:


text
(3, 3)

Private Tests ( 2/2 )

Case 1

Input:


text
is_equal(final_position((-1,1), (4,4), 3), (11,13))

Case 1

Expected Output:


text
(11, 13)

Case 1

Actual Output:


text
(11, 13)

Case 2

Input:


text
is_equal(final_position((2,2), (8,2), 0), (2,2))
is_equal(final_position((1,-4), (1,4), 2), (3,4))

Case 2

Expected Output:


text
(2, 2)

(3, 4)

Case 2

Actual Output:


text
(2, 2)

(3, 4)

💻 IITM Official Solution


python

def final_position(pos: tuple, vel: tuple, time:int) -> tuple:
    '''
    Given an initial position of a point moving in a cartesian plane with a constant velocity,
    find the the final position of the point after a given time.

    Hint: final position = intial position + velocity * time

    Args:
        pos - tuple[int]: A tuple representing the position vector (x1, y1).
        vel - tuple[int]: A tuple representing the velocity vector (vx, vy).
        time - int: time of movement.

    Returns:
        tuple[int]: A tuple representing the displacement (dx, dy).
    '''


    x1, y1 = pos
    vx, vy = vel
    return (x1+vx*time , y1+vy*time)

💻 My Submitted Code


python
def final_position(pos: tuple, vel: tuple, time: int) -> tuple:
    # 1. Unpack the coordinates and velocities
    x, y = pos
    vx, vy = vel

    # 2. Apply the formula: final = initial + (velocity * time)
    xf = x + (vx * time)
    yf = y + (vy * time)

    return (xf, yf)