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jan-2026-python-week-7-numbers-3

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Numbers 3

Course: Jan 2026 - Python

Numbers 3

Submission deadline has passed for this assignment

Due Apr 01, 2026 at 11:59 PM IST

Instructions

Use "Test Run" to verify your code with public test cases.

Press "Submit" to have your assignment evaluated.

You can submit your assignment multiple times up until the deadline.

Make sure to submit your final code by the deadline to receive your score.

Summary

100 out of100

Score

Public Tests

3/3 Passed

Submitted on Apr 01, 2026 at 3:46 AM IST

Private Tests

3/3 Passed

Submitted on Apr 01, 2026 at 3:46 AM IST

**Change in eligibility criteria to write oppe2 exam: A5>=40/100 AND A6>=40/100 AND A7>=40/100 AND A8>=40/100. and becoming eligible to give the end term exam.

Find Manhattan distance between two 2d points through a point**

Given three points a, b, and c on the Cartesian plane, calculate the Manhattan distance to go from point a to point c via point b.

Manhattan distance is the sum of the absolute differences of their Cartesian coordinates.

Template Code(Click to Expand)



def manhattan_distance_via_b(a: tuple, b: tuple, c: tuple) -> int:
    '''
    Given three points a, b, and c on the Cartesian plane,
    calculate the Manhattan distance to go from point a to point c via point b.

    Manhattan distance is the sum of the absolute differences of their Cartesian coordinates.

    Args:
        a (tuple): Coordinates of point a as (x1, y1).
        b (tuple): Coordinates of point b as (x2, y2).
        c (tuple): Coordinates of point c as (x3, y3).

    Returns:
        int: The Manhattan distance from point a to point c via point b.
    '''
    ...

NOTE: You can use the below tools for working out and debugging. Click to open them in new tab.

PythonTutor | Starboard Notebook | Pyodide Terminal

Public Tests ( 3/3 )

Case 1

Input:


text
a = (1, 2)
b = (3, 4)
c = (6, 7)
d = manhattan_distance_via_b(a, b, c)
is_equal(d, 10)

Case 1

Expected Output:


text
10

Case 1

Actual Output:


text
10

Case 2

Input:


text
a = (0, 0)
b = (2, 2)
c = (3, 3)
d = manhattan_distance_via_b(a, b, c)
is_equal(d, 6)

Case 2

Expected Output:


text
6

Case 2

Actual Output:


text
6

Case 3

Input:


text
a = (-1, -1)
b = (1, 1)
c = (2, 2)
d = manhattan_distance_via_b(a, b, c)
is_equal(d, 6)

Private Tests ( 3/3 )

Case 1

Input:


text
a1 = (5, 5)
b1 = (0, 0)
c1 = (10, 10)
result = manhattan_distance_via_b(a1, b1, c1)
is_equal(result, 30)

Case 1

Expected Output:


text
30

Case 1

Actual Output:


text
30

Case 2

Input:


text
a2 = (7, 8)
b2 = (2, 3)
c2 = (4, 1)
result = manhattan_distance_via_b(a2, b2, c2)
is_equal(result, 14)

Case 2

Expected Output:


text
14

Case 2

Actual Output:


text
14

Case 3

Input:


text
a3 = (-5, -5)
b3 = (0, 0)
c3 = (5, 5)
result = manhattan_distance_via_b(a3, b3, c3)
is_equal(result, 20)

Case 3

Expected Output:


text
20

Case 3

Actual Output:


text
20

💻 IITM Official Solution


python

def manhattan_distance_via_b(a: tuple, b: tuple, c: tuple) -> int:
    '''
    Given three points a, b, and c on the Cartesian plane,
    calculate the Manhattan distance to go from point a to point c via point b.

    Manhattan distance is the sum of the absolute differences of their Cartesian coordinates.

    Args:
        a (tuple): Coordinates of point a as (x1, y1).
        b (tuple): Coordinates of point b as (x2, y2).
        c (tuple): Coordinates of point c as (x3, y3).

    Returns:
        int: The Manhattan distance from point a to point c via point b.
    '''


    x1,y1,x2,y2,x3,y3 = a+b+c
    a2b = abs(x1 - x2) + abs(y1 - y2)
    b2c = abs(x2 - x3) + abs(y2 - y3)
    return a2b+b2c

💻 My Submitted Code


python
def manhattan_distance_via_b(a: tuple, b: tuple, c: tuple) -> int:
    # Manhattan distance = |x1 - x2| + |y1 - y2|
    # Distance from a to b
    dist_ab = abs(a[0] - b[0]) + abs(a[1] - b[1])
    # Distance from b to c
    dist_bc = abs(b[0] - c[0]) + abs(b[1] - c[1])

    return dist_ab + dist_bc