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jan-2026-python-week-7-strings-4

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Strings 4

Course: Jan 2026 - Python

Strings 4

Submission deadline has passed for this assignment

Due Apr 01, 2026 at 11:59 PM IST

Instructions

Use "Test Run" to verify your code with public test cases.

Press "Submit" to have your assignment evaluated.

You can submit your assignment multiple times up until the deadline.

Make sure to submit your final code by the deadline to receive your score.

Summary

100 out of100

Score

Public Tests

3/3 Passed

Submitted on Apr 01, 2026 at 3:48 AM IST

Private Tests

3/3 Passed

Submitted on Apr 01, 2026 at 3:48 AM IST

**Change in eligibility criteria to write oppe2 exam: A5>=40/100 AND A6>=40/100 AND A7>=40/100 AND A8>=40/100. and becoming eligible to give the end term exam.

Remove First two and Last two Chars from a string**

Given a string s, return a new string with the first two and last two characters removed.

If the string has less than four characters return an empty string.

Example


s = 'HelloWorld'

Removing the first two and last two characters results in 'lloWor'.

Template Code(Click to Expand)




def remove_edges(s: str) -> str:
    '''
    Return a new string with the first two and last two
    characters removed from the given string.

    Arguments:
    s: str - a string.

    Return: str - a string with first and last two characters removed.
    '''
    ...

NOTE: You can use the below tools for working out and debugging. Click to open them in new tab.

PythonTutor | Starboard Notebook | Pyodide Terminal

Public Tests ( 3/3 )

Case 1

Input:


text
s = 'abcdef'
is_equal(
    remove_edges(s),
    'cd'
)

Case 1

Expected Output:


text
'cd'

Case 1

Actual Output:


text
'cd'

Case 2

Input:


text
s = 'abcdefghij'
is_equal(
    remove_edges(s),
    'cdefgh'
)

Case 2

Expected Output:


text
'cdefgh'

Case 2

Actual Output:


text
'cdefgh'

Case 3

Input:


text
s = 'abcd'
is_equal(
    remove_edges(s),
    '' # empty string
)

Case 3

Expected Output:


text
''

Case 3

Actual Output:


text
''

Private Tests ( 3/3 )

Case 1

Input:


text
s = 'HelloWorld'
is_equal(
    remove_edges(s),
    'lloWor'
)

Case 1

Expected Output:


text
'lloWor'

Case 1

Actual Output:


text
'lloWor'

Case 2

Input:


text
s = 'Mountain'
is_equal(
    remove_edges(s),
    'unta'
)

Case 2

Expected Output:


text
'unta'

Case 2

Actual Output:


text
'unta'

Case 3

Input:


text
s = '123456789'
is_equal(
    remove_edges(s),
    '34567'
)

Case 3

Expected Output:


text
'34567'

Case 3

Actual Output:


text
'34567'

💻 IITM Official Solution


python


def remove_edges(s: str) -> str:
    '''
    Return a new string with the first two and last two
    characters removed from the given string.

    Arguments:
    s: str - a string.

    Return: str - a string with first and last two characters removed.
    '''


    return s[2:-2]

💻 My Submitted Code


python
def remove_edges(s: str) -> str:
    # Check length constraint
    if len(s) < 4:
        return ""

    # Slice from index 2 up to the 2nd character from the end
    return s[2:-2]