Exponential Functions
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# Exponential Functions ## ๐ฏ Learning Objectives By the end of this topic, you will be able to: 1. **Define** exponential functions and distinguish them from polynomials 2.

Exponential Functions
๐ฏ Learning Objectives
By the end of this topic, you will be able to:
- Define exponential functions and distinguish them from polynomials
- Apply the laws of exponents
- Graph exponential functions for a>1 and 0<a<1
- Identify exponential growth vs. decay
- Use the natural exponential function ex
- Apply the vertical and horizontal line tests to graphs
๐ Prerequisites
- Functions โ domain, range, function notation
- Exponent rules โ amโ an=am+n, (am)n=amn, a0=1
- Polynomials โ basic graphing concepts
๐ Core Content
6.1 Exponential vs. Polynomial
6.1.1 Intuition
A polynomial like x2 grows by multiplying the base (x) by itself. An exponential like 2x grows by multiplying the exponent (x) by 2 each step.
The difference is dramatic: x2 gives 1,4,9,16,25,โฆ while 2x gives 2,4,8,16,32,โฆ. Eventually, exponentials outpace any polynomial.
๐ก Why this matters: Exponentials model growth processes: population, compound interest, viral spread, machine learning training time (sometimes). Decay processes: radioactive decay, cooling, forgetting curves.
6.1.2 Definition
An exponential function has the form:
where a>0 and a๎ =1 is the base, and x is the exponent.
| Base | Behavior | Example |
|---|---|---|
| a>1 | Exponential growth | 2x , 3x , ex |
| 0<a<1 | Exponential decay | (1/2)x , 0.1x |
Key property: a0=1 for any a๎ =0, so every exponential passes through (0,1).
6.2 Laws of Exponents
| Law | Formula | Example |
|---|---|---|
| Product | amโ an=am+n | 23โ 24=27 |
| Quotient | am/an=amโn | 35/32=33 |
| Power | (am)n=amn | (52)3=56 |
| Negative | aโn=1/an | 2โ3=1/8 |
| Zero | a0=1 (if a๎ =0 ) | 70=1 |
| Fractional | am/n=namโ | 82/3=382โ=4 |
| Distributive | (ab)n=anbn | (2โ 3)2=36 |
| (a/b)n=an/bn | (4/2)3=8 |
6.3 Graphing Exponential Functions
6.3.1 Graph of f(x)=ax, a>1 (Growth)
For f(x)=2x:
| x | โ3 | โ2 | โ1 | 0 | 1 | 2 | 3 |
|---|---|---|---|---|---|---|---|
| f(x) | 1/8 | 1/4 | 1/2 | 1 | 2 | 4 | 8 |
Properties:
- Domain: R (all real numbers)
- Range: (0,โ) (always positive)
- y-intercept: (0,1)
- Horizontal asymptote: y=0 (x-axis) as xโโโ
- Increasing, convex (curving upward)
6.3.2 Graph of f(x)=ax, 0<a<1 (Decay)
For f(x)=(1/2)x:
| x | โ3 | โ2 | โ1 | 0 | 1 | 2 | 3 |
|---|---|---|---|---|---|---|---|
| f(x) | 8 | 4 | 2 | 1 | 1/2 | 1/4 | 1/8 |
Properties:
- Domain: R, Range: (0,โ)
- y-intercept: (0,1)
- Horizontal asymptote: y=0 as xโโ
- Decreasing, convex (curving upward)
๐ Note: (1/2)x=2โx. So decay functions are reflections of growth functions across the y-axis. (Diagram)
6.4 The Natural Exponential Function
The natural exponential f(x)=ex has base eโ2.71828โฆ, which is an irrational number (like ฯ).
Why e? It's the "natural" base for growth processes โ continuous compounding, population growth, and it's its own derivative (key in calculus!).
Example โ Continuous Compounding: If you invest 100at5tyears:A(t) = 100 \cdot e^{0.05t}$.
6.5 Vertical and Horizontal Line Tests
6.5.1 Vertical Line Test (VLT)
A graph represents a function iff no vertical line intersects it more than once.
All exponential functions pass the VLT (they're functions).
6.5.2 Horizontal Line Test (HLT)
A function is injective (one-to-one) iff no horizontal line intersects its graph more than once.
All exponential functions f(x)=ax (with a>0, a๎ =1) pass the HLT โ they are injective. This means they have inverses (logarithms!).
6.6 Worked Examples
Example 6.1 (Growth): The population of a city grows at 3% per year. If the current population is 500,000, find the population after 10 years.
Step 1: P(t)=P0โโ
at, where a=1+0.03=1.03, P0โ=500000
Step 2: P(10)=500000โ
(1.03)10
Step 3: (1.03)10โ1.3439
Step 4: P(10)โ500000ร1.3439=671958
Example 6.2 (Decay): A radioactive isotope decays with half-life 5 years. If we start with 100g, how much remains after 20 years?
Step 1: Half-life means N(t)=N0โโ
(1/2)t/5
Step 2: N(20)=100โ
(1/2)20/5=100โ
(1/2)4=100โ
161โ=6.25
Example 6.3 (Natural exponential): Simplify e3xโ
eโ2xโ
e0.
Step 1: e3xโ
eโ2xโ
e0=e3x+(โ2x)+0=ex
๐ Key Formulas โ Summary Table
| Concept | Formula | Notes |
|---|---|---|
| Exponential function | f(x)=ax , a>0 , a๎ =1 | |
| Growth | a>1 | Increasing |
| Decay | 0<a<1 | Decreasing |
| e | eโ2.71828 | Natural base |
| Product | amโ an=am+n | |
| Quotient | am/an=amโn | |
| Power | (am)n=amn | |
| Negative | aโn=1/an | |
| Fractional | am/n=namโ | |
| HLT | Exponential passes โ injective | Inverse exists (log) |
| Domain | R | |
| Range | (0,โ) | |
| y -intercept | (0,1) | |
| Asymptote | y=0 | Horizontal |
โ ๏ธ Common Pitfalls
Pitfall 1: Confusing xn with nx
xn is polynomial (base varies, exponent fixed); nx is exponential (base fixed, exponent varies). Very different behavior!
Pitfall 2: Thinking a0=0
Actually a0=1 (for a๎ =0). This is why every exponential passes through (0,1).
Pitfall 3: Forgetting the Domains Are All Reals
Exponential functions accept any real input, including irrationals. 22โ is well-defined.
Pitfall 4: Assuming e is a Variable
e is a constant (โ2.718), not a variable. ex is the exponential function with base e.
๐ Practice Questions
Q1: Evaluate 3โ2โ 34.Strategy Hint: Use product law.3โ2+4=32=99โ Q2: Simplify (23)4รท27.Strategy Hint: Power law then quotient law.(23)4=212; 212รท27=25=3232โ Q3: Graph f(x)=3x and state its range.Strategy Hint: Plot points for x=โ2,โ1,0,1,2.Range: (0,โ)(0,โ)โ Q4: Is f(x)=2x+1 injective?Strategy Hint: Check HLT โ horizontal lines intersect at most once?Yes, 2x is injective, adding 1 shifts it up but doesn't change injectivity.Yesโ Q5: Simplify e3xe2xโ eโxโ.Strategy Hint: Combine exponents in numerator, then subtract.=e3xexโ=exโ3x=eโ2xeโ2xโ Q6: A bacteria culture doubles every 3 hours. If initial count is 1000, find count after 12 hours.Strategy Hint: N(t)=N0โโ 2t/3.N(12)=1000โ 24=1000โ 16=1600016,000โ Q7: Determine if f(x)=(32โ)x represents growth or decay.Strategy Hint: Base = 2/3โ0.667<1.Decay.Decayโ Q8: Compute (8)โ2/3.Strategy Hint: 8โ2/3=82/31โ=(38โ)21โ=221โ=41โ.41โโ Q9: If f(x)=2x+1, find f(3).f(3)=24=1616โ Q10: The half-life of a drug in the body is 6 hours. If a patient takes 200mg, how much remains after 24 hours?N(24)=200โ (1/2)24/6=200โ (1/2)4=200โ 1/16=12.512.5ย mgโ Q11: Write 2โโ 32โ in the form 2x.2โ=21/2, 32โ=21/3. Product: 21/2+1/3=25/625/6โ Q12: If a function fails the horizontal line test, does it pass the vertical line test?Strategy Hint: These tests check different things.HLT checks injectivity. VLT checks if it's a function. A function can fail HLT (not injective) but always passes VLT.Yesย โย itโsย stillย aย functionย butย notย injectiveโ
๐ Cross-References
- Next topic: Composite and Inverse Functions
- Related: Logarithms โ the inverse of exponentials
- Across courses: BSMA1003 Maths 2 (exponential functions in differential equations); BSMA1002 Stats 1 (exponential distributions, growth models) Join Discord Previous4.0 Polynomial OperationsNext5.2 Composite & Inverse Functions