Quiz 2

Exponential Functions

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# Exponential Functions ## 🎯 Learning Objectives By the end of this topic, you will be able to: 1. **Define** exponential functions and distinguish them from polynomials 2.

Exponential Functions

🎯 Learning Objectives

By the end of this topic, you will be able to:
  1. Define exponential functions and distinguish them from polynomials
  2. Apply the laws of exponents
  3. Graph exponential functions for a>1a > 1 and 0<a<10 < a < 1
  4. Identify exponential growth vs. decay
  5. Use the natural exponential function exe^x
  6. Apply the vertical and horizontal line tests to graphs

📋 Prerequisites

  • Functions — domain, range, function notation
  • Exponent rulesaman=am+na^m \cdot a^n = a^{m+n}, (am)n=amn(a^m)^n = a^{mn}, a0=1a^0 = 1
  • Polynomials — basic graphing concepts

📖 Core Content

6.1 Exponential vs. Polynomial

6.1.1 Intuition

A polynomial like x2x^2 grows by multiplying the base (xx) by itself. An exponential like 2x2^x grows by multiplying the exponent (xx) by 2 each step. The difference is dramatic: x2x^2 gives 1,4,9,16,25,1, 4, 9, 16, 25, \ldots while 2x2^x gives 2,4,8,16,32,2, 4, 8, 16, 32, \ldots. Eventually, exponentials outpace any polynomial.
💡 Why this matters: Exponentials model growth processes: population, compound interest, viral spread, machine learning training time (sometimes). Decay processes: radioactive decay, cooling, forgetting curves.

6.1.2 Definition

An exponential function has the form:
f(x)=axf(x) = a^x
where a>0a > 0 and a1a \neq 1 is the base, and xx is the exponent.
BaseBehaviorExample
a>1a > 1Exponential growth2x2^x , 3x3^x , exe^x
0<a<10 < a < 1Exponential decay(1/2)x(1/2)^x , 0.1x0.1^x
Key property: a0=1a^0 = 1 for any a0a \neq 0, so every exponential passes through (0,1)(0, 1).

6.2 Laws of Exponents

LawFormulaExample
Productaman=am+na^m \cdot a^n = a^{m+n}2324=272^3 \cdot 2^4 = 2^7
Quotientam/an=amna^m / a^n = a^{m-n}35/32=333^5 / 3^2 = 3^3
Power(am)n=amn(a^m)^n = a^{mn}(52)3=56(5^2)^3 = 5^6
Negativean=1/ana^{-n} = 1/a^n23=1/82^{-3} = 1/8
Zeroa0=1a^0 = 1 (if a0a \neq 0 )70=17^0 = 1
Fractionalam/n=amna^{m/n} = \sqrt[n]{a^m}82/3=823=48^{2/3} = \sqrt[3]{8^2} = 4
Distributive(ab)n=anbn(ab)^n = a^n b^n(23)2=36(2 \cdot 3)^2 = 36
(a/b)n=an/bn(a/b)^n = a^n / b^n(4/2)3=8(4/2)^3 = 8

6.3 Graphing Exponential Functions

6.3.1 Graph of f(x)=axf(x) = a^x, a>1a > 1 (Growth)

For f(x)=2xf(x) = 2^x:
xx3-32-21-100112233
f(x)f(x)1/81/81/41/41/21/211224488
Properties:
  • Domain: R\mathbb{R} (all real numbers)
  • Range: (0,)(0, \infty) (always positive)
  • yy-intercept: (0,1)(0, 1)
  • Horizontal asymptote: y=0y = 0 (x-axis) as xx \to -\infty
  • Increasing, convex (curving upward)

6.3.2 Graph of f(x)=axf(x) = a^x, 0<a<10 < a < 1 (Decay)

For f(x)=(1/2)xf(x) = (1/2)^x:
xx3-32-21-100112233
f(x)f(x)884422111/21/21/41/41/81/8
Properties:
  • Domain: R\mathbb{R}, Range: (0,)(0, \infty)
  • yy-intercept: (0,1)(0, 1)
  • Horizontal asymptote: y=0y = 0 as xx \to \infty
  • Decreasing, convex (curving upward)
🔍 Note: (1/2)x=2x(1/2)^x = 2^{-x}. So decay functions are reflections of growth functions across the yy-axis. (Diagram)

6.4 The Natural Exponential Function

The natural exponential f(x)=exf(x) = e^x has base e2.71828e \approx 2.71828\ldots, which is an irrational number (like π\pi).
e=limn(1+1n)n2.718281828459045e = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n \approx 2.718281828459045\ldots
Why ee? It's the "natural" base for growth processes — continuous compounding, population growth, and it's its own derivative (key in calculus!). Example — Continuous Compounding: If you invest 100at5100 at 5% annual interest compounded continuously, after tyears:years:A(t) = 100 \cdot e^{0.05t}$.

6.5 Vertical and Horizontal Line Tests

6.5.1 Vertical Line Test (VLT)

A graph represents a function iff no vertical line intersects it more than once. All exponential functions pass the VLT (they're functions).

6.5.2 Horizontal Line Test (HLT)

A function is injective (one-to-one) iff no horizontal line intersects its graph more than once. All exponential functions f(x)=axf(x) = a^x (with a>0a > 0, a1a \neq 1) pass the HLT — they are injective. This means they have inverses (logarithms!).

6.6 Worked Examples

Example 6.1 (Growth): The population of a city grows at 3% per year. If the current population is 500,000, find the population after 10 years. Step 1: P(t)=P0atP(t) = P_0 \cdot a^t, where a=1+0.03=1.03a = 1 + 0.03 = 1.03, P0=500000P_0 = 500000 Step 2: P(10)=500000(1.03)10P(10) = 500000 \cdot (1.03)^{10} Step 3: (1.03)101.3439(1.03)^{10} \approx 1.3439 Step 4: P(10)500000×1.3439=671958P(10) \approx 500000 \times 1.3439 = 671958
672,000\boxed{\approx 672,000}
Example 6.2 (Decay): A radioactive isotope decays with half-life 5 years. If we start with 100g, how much remains after 20 years? Step 1: Half-life means N(t)=N0(1/2)t/5N(t) = N_0 \cdot (1/2)^{t/5} Step 2: N(20)=100(1/2)20/5=100(1/2)4=100116=6.25N(20) = 100 \cdot (1/2)^{20/5} = 100 \cdot (1/2)^4 = 100 \cdot \frac{1}{16} = 6.25
6.25 grams\boxed{6.25 \text{ grams}}
Example 6.3 (Natural exponential): Simplify e3xe2xe0e^{3x} \cdot e^{-2x} \cdot e^{0}. Step 1: e3xe2xe0=e3x+(2x)+0=exe^{3x} \cdot e^{-2x} \cdot e^0 = e^{3x + (-2x) + 0} = e^{x}
ex\boxed{e^x}

📐 Key Formulas — Summary Table

ConceptFormulaNotes
Exponential functionf(x)=axf(x) = a^x , a>0a > 0 , a1a \neq 1
Growtha>1a > 1Increasing
Decay0<a<10 < a < 1Decreasing
eee2.71828e \approx 2.71828Natural base
Productaman=am+na^m \cdot a^n = a^{m+n}
Quotientam/an=amna^m / a^n = a^{m-n}
Power(am)n=amn(a^m)^n = a^{mn}
Negativean=1/ana^{-n} = 1/a^n
Fractionalam/n=amna^{m/n} = \sqrt[n]{a^m}
HLTExponential passes → injectiveInverse exists (log)
DomainR\mathbb{R}
Range(0,)(0, \infty)
yy -intercept(0,1)(0, 1)
Asymptotey=0y = 0Horizontal

⚠️ Common Pitfalls

Pitfall 1: Confusing xnx^n with nxn^x

xnx^n is polynomial (base varies, exponent fixed); nxn^x is exponential (base fixed, exponent varies). Very different behavior!

Pitfall 2: Thinking a0=0a^0 = 0

Actually a0=1a^0 = 1 (for a0a \neq 0). This is why every exponential passes through (0,1)(0, 1).

Pitfall 3: Forgetting the Domains Are All Reals

Exponential functions accept any real input, including irrationals. 222^{\sqrt{2}} is well-defined.

Pitfall 4: Assuming ee is a Variable

ee is a constant (2.718\approx 2.718), not a variable. exe^x is the exponential function with base ee.

📝 Practice Questions

Q1: Evaluate 32343^{-2} \cdot 3^4.
Strategy Hint: Use product law.
32+4=32=93^{-2+4} = 3^2 = 9
9\boxed{9} Q2: Simplify (23)4÷27(2^3)^4 \div 2^7.
Strategy Hint: Power law then quotient law.
(23)4=212(2^3)^4 = 2^{12}; 212÷27=25=322^{12} \div 2^7 = 2^5 = 32
32\boxed{32} Q3: Graph f(x)=3xf(x) = 3^x and state its range.
Strategy Hint: Plot points for x=2,1,0,1,2x = -2, -1, 0, 1, 2.
Range: (0,)(0, \infty)
(0,)\boxed{(0, \infty)} Q4: Is f(x)=2x+1f(x) = 2^x + 1 injective?
Strategy Hint: Check HLT — horizontal lines intersect at most once?
Yes, 2x2^x is injective, adding 1 shifts it up but doesn't change injectivity.
Yes\boxed{\text{Yes}} Q5: Simplify e2xexe3x\frac{e^{2x} \cdot e^{-x}}{e^{3x}}.
Strategy Hint: Combine exponents in numerator, then subtract.
=exe3x=ex3x=e2x= \frac{e^{x}}{e^{3x}} = e^{x-3x} = e^{-2x}
e2x\boxed{e^{-2x}} Q6: A bacteria culture doubles every 3 hours. If initial count is 1000, find count after 12 hours.
Strategy Hint: N(t)=N02t/3N(t) = N_0 \cdot 2^{t/3}.
N(12)=100024=100016=16000N(12) = 1000 \cdot 2^{4} = 1000 \cdot 16 = 16000
16,000\boxed{16,000} Q7: Determine if f(x)=(23)xf(x) = \left(\frac{2}{3}\right)^x represents growth or decay.
Strategy Hint: Base = 2/30.667<12/3 \approx 0.667 < 1.
Decay.
Decay\boxed{\text{Decay}} Q8: Compute (8)2/3(8)^{-2/3}.
Strategy Hint: 82/3=182/3=1(83)2=122=148^{-2/3} = \frac{1}{8^{2/3}} = \frac{1}{(\sqrt[3]{8})^2} = \frac{1}{2^2} = \frac{1}{4}.
14\boxed{\frac{1}{4}} Q9: If f(x)=2x+1f(x) = 2^{x+1}, find f(3)f(3).
f(3)=24=16f(3) = 2^{4} = 16
16\boxed{16} Q10: The half-life of a drug in the body is 6 hours. If a patient takes 200mg, how much remains after 24 hours?
N(24)=200(1/2)24/6=200(1/2)4=2001/16=12.5N(24) = 200 \cdot (1/2)^{24/6} = 200 \cdot (1/2)^4 = 200 \cdot 1/16 = 12.5
12.5 mg\boxed{12.5 \text{ mg}} Q11: Write 223\sqrt{2} \cdot \sqrt[3]{2} in the form 2x2^x.
2=21/2\sqrt{2} = 2^{1/2}, 23=21/3\sqrt[3]{2} = 2^{1/3}. Product: 21/2+1/3=25/62^{1/2 + 1/3} = 2^{5/6}
25/6\boxed{2^{5/6}} Q12: If a function fails the horizontal line test, does it pass the vertical line test?
Strategy Hint: These tests check different things.
HLT checks injectivity. VLT checks if it's a function. A function can fail HLT (not injective) but always passes VLT.
Yes — it’s still a function but not injective\boxed{\text{Yes — it's still a function but not injective}}

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