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# Mathematics I · Week 7 — Limits and continuity Deep study for Quiz 2 week 7. Limits describe approaching behavior; continuity requires the approach to match the actual value.

Mathematics I · Week 7 — Limits and continuity
Deep study for Quiz 2 week 7. Limits describe approaching behavior; continuity requires the approach to match the actual value.
Week map
Sequence terms → limit intuition → one-sided limits → two-sided limit → continuity at a point → types of discontinuity.
Limit notation
- limx→af(x)=L → “limit of f(x) as x approaches a is L” → value f tends toward near a, not necessarily at a.
- limx→a−f(x) → left-hand limit → approach from values less than a.
- limx→a+f(x) → right-hand limit → approach from values greater than a.
- limx→af(x) exists iff left and right limits exist and are equal.
Mini-example: f(x)=x−1x2−1 for x=1. Near x=1: factor to x+1, so limx→1f(x)=2, even though f(1) is undefined.
Sequence limits
- limn→∞an=L → terms an get arbitrarily close to L as n grows.
- For rational sequences, divide numerator and denominator by highest power of n to guess limit.
Mini-example: an=n+23n+1. Divide top and bottom by n: 1+2/n3+1/n→3 as n→∞.
Continuity notation
- Continuous at a: limx→af(x)=f(a) — limit exists, function defined, and they agree.
- Removable discontinuity: limit exists but f(a) missing or wrong — “hole” in graph.
- Jump discontinuity: left and right limits exist but differ.
- Infinite discontinuity: limit blows up to ±∞.
Mini-example: f(x)=∣x∣/x at x=0. Left limit −1, right limit +1 — jump discontinuity.
Pattern families
Easy — Sequence pattern
Write first several terms from formula. Describe trend. Guess limit by table or simplifying for large n.
Medium — One-sided and two-sided limits
Evaluate limits from graphs. Identify left vs right behavior at breakpoints, absolute value corners, piecewise joins.
Hard — Continuity classification
Decide if function is continuous at a point. Identify discontinuity type. State what value would make function continuous (removable case).
Worked mini-examples
Example 1 — Direct substitution.
limx→3(2x+5)=11 — polynomial, no issue.
Example 2 — Cancel factor.
limx→2x−2x2−4=limx→2(x+2)=4.
Example 3 — One-sided.
f(x)={x+1x2x<0x≥0. Left at 0: 1; right at 0: 0. Two-sided limit does not exist.
Example 4 — Sequence.
an=n1→0 as n→∞.
Example 5 — Removable.
f(x)=xsinx for x=0, f(0)=0. limx→0xsinx=1=f(0) — removable if redefine f(0)=1.
Traps
- Assuming limx→af(x)=f(a) without checking.
- Ignoring one-sided limits at piecewise boundaries.
- Thinking limit at infinity means function equals that value.
- Canceling (x−a) without noting hole at x=a.
- Sequence limit confused with finite term value.
Diagnostic (try yourself)
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Find limx→5(x2−3x).
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Evaluate limx→1x−1x2−1.
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For f(x)=x∣x∣, what are the left and right limits at x=0?
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Sequence an=n+52n: what value does an approach as n→∞?
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A function has limx→2f(x)=7 but f(2)=3. Is it continuous at 2? What type of issue is this?