Neural Sync Active
Exponential Functions
Registry Synced
Exponential Functions
1598 words
8 min read
Reading compass
Now · 🎯 Learning Objectives
Exponential Functions
🎯 Learning Objectives
By the end of this topic, you will be able to:
- Define exponential functions and distinguish them from polynomials
- Apply the laws of exponents
- Graph exponential functions for a>1 and 0<a<1
- Identify exponential growth vs. decay
- Use the natural exponential function ex
- Apply the vertical and horizontal line tests to graphs
📋 Prerequisites
- Functions — domain, range, function notation
- Exponent rules — am⋅an=am+n, (am)n=amn, a0=1
- Polynomials — basic graphing concepts
📖 Core Content
6.1 Exponential vs. Polynomial
6.1.1 Intuition
A polynomial like x2 grows by multiplying the base (x) by itself. An exponential like 2x grows by multiplying the exponent (x) by 2 each step.
The difference is dramatic: x2 gives 1,4,9,16,25,… while 2x gives 2,4,8,16,32,…. Eventually, exponentials outpace any polynomial.
💡 Why this matters: Exponentials model growth processes: population, compound interest, viral spread, machine learning training time (sometimes). Decay processes: radioactive decay, cooling, forgetting curves.
6.1.2 Definition
An exponential function has the form:
where a>0 and a=1 is the base, and x is the exponent.
| Base | Behavior | Example |
|---|---|---|
| a>1 | Exponential growth | 2x , 3x , ex |
| 0<a<1 | Exponential decay | (1/2)x , 0.1x |
Key property: a0=1 for any a=0, so every exponential passes through (0,1).
6.2 Laws of Exponents
| Law | Formula | Example |
|---|---|---|
| Product | am⋅an=am+n | 23⋅24=27 |
| Quotient | am/an=am−n | 35/32=33 |
| Power | (am)n=amn | (52)3=56 |
| Negative | a−n=1/an | 2−3=1/8 |
| Zero | a0=1 (if a=0 ) | 70=1 |
| Fractional | am/n=nam | 82/3=382=4 |
| Distributive | (ab)n=anbn | (2⋅3)2=36 |
| (a/b)n=an/bn | (4/2)3=8 |
6.3 Graphing Exponential Functions
6.3.1 Graph of f(x)=ax, a>1 (Growth)
For f(x)=2x:
| x | −3 | −2 | −1 | 0 | 1 | 2 | 3 |
|---|---|---|---|---|---|---|---|
| f(x) | 1/8 | 1/4 | 1/2 | 1 | 2 | 4 | 8 |
Properties:
- Domain: R (all real numbers)
- Range: (0,∞) (always positive)
- y-intercept: (0,1)
- Horizontal asymptote: y=0 (x-axis) as x→−∞
- Increasing, convex (curving upward)
6.3.2 Graph of f(x)=ax, 0<a<1 (Decay)
For f(x)=(1/2)x:
| x | −3 | −2 | −1 | 0 | 1 | 2 | 3 |
|---|---|---|---|---|---|---|---|
| f(x) | 8 | 4 | 2 | 1 | 1/2 | 1/4 | 1/8 |
Properties:
- Domain: R, Range: (0,∞)
- y-intercept: (0,1)
- Horizontal asymptote: y=0 as x→∞
- Decreasing, convex (curving upward)
🔍 Note: (1/2)x=2−x. So decay functions are reflections of growth functions across the y-axis. (Diagram)
6.4 The Natural Exponential Function
The natural exponential f(x)=ex has base e≈2.71828…, which is an irrational number (like π).
Why e? It's the "natural" base for growth processes — continuous compounding, population growth, and it's its own derivative (key in calculus!).
Example — Continuous Compounding: If you invest 100at5tyears:A(t) = 100 \cdot e^{0.05t}$.
6.5 Vertical and Horizontal Line Tests
6.5.1 Vertical Line Test (VLT)
A graph represents a function iff no vertical line intersects it more than once.
All exponential functions pass the VLT (they're functions).
6.5.2 Horizontal Line Test (HLT)
A function is injective (one-to-one) iff no horizontal line intersects its graph more than once.
All exponential functions f(x)=ax (with a>0, a=1) pass the HLT — they are injective. This means they have inverses (logarithms!).
6.6 Worked Examples
Example 6.1 (Growth): The population of a city grows at 3% per year. If the current population is 500,000, find the population after 10 years.
Step 1: P(t)=P0⋅at, where a=1+0.03=1.03, P0=500000
Step 2: P(10)=500000⋅(1.03)10
Step 3: (1.03)10≈1.3439
Step 4: P(10)≈500000×1.3439=671958
Example 6.2 (Decay): A radioactive isotope decays with half-life 5 years. If we start with 100g, how much remains after 20 years?
Step 1: Half-life means N(t)=N0⋅(1/2)t/5
Step 2: N(20)=100⋅(1/2)20/5=100⋅(1/2)4=100⋅161=6.25
Example 6.3 (Natural exponential): Simplify e3x⋅e−2x⋅e0.
Step 1: e3x⋅e−2x⋅e0=e3x+(−2x)+0=ex
📐 Key Formulas — Summary Table
| Concept | Formula | Notes |
|---|---|---|
| Exponential function | f(x)=ax , a>0 , a=1 | |
| Growth | a>1 | Increasing |
| Decay | 0<a<1 | Decreasing |
| e | e≈2.71828 | Natural base |
| Product | am⋅an=am+n | |
| Quotient | am/an=am−n | |
| Power | (am)n=amn | |
| Negative | a−n=1/an | |
| Fractional | am/n=nam | |
| HLT | Exponential passes → injective | Inverse exists (log) |
| Domain | R | |
| Range | (0,∞) | |
| y -intercept | (0,1) | |
| Asymptote | y=0 | Horizontal |
⚠️ Common Pitfalls
Pitfall 1: Confusing xn with nx
xn is polynomial (base varies, exponent fixed); nx is exponential (base fixed, exponent varies). Very different behavior!
Pitfall 2: Thinking a0=0
Actually a0=1 (for a=0). This is why every exponential passes through (0,1).
Pitfall 3: Forgetting the Domains Are All Reals
Exponential functions accept any real input, including irrationals. 22 is well-defined.
Pitfall 4: Assuming e is a Variable
e is a constant (≈2.718), not a variable. ex is the exponential function with base e.
📝 Practice Questions
Q1: Evaluate 3−2⋅34.Strategy Hint: Use product law.3−2+4=32=99 Q2: Simplify (23)4÷27.Strategy Hint: Power law then quotient law.(23)4=212; 212÷27=25=3232 Q3: Graph f(x)=3x and state its range.Strategy Hint: Plot points for x=−2,−1,0,1,2.Range: (0,∞)(0,∞) Q4: Is f(x)=2x+1 injective?Strategy Hint: Check HLT — horizontal lines intersect at most once?Yes, 2x is injective, adding 1 shifts it up but doesn't change injectivity.Yes Q5: Simplify e3xe2x⋅e−x.Strategy Hint: Combine exponents in numerator, then subtract.=e3xex=ex−3x=e−2xe−2x Q6: A bacteria culture doubles every 3 hours. If initial count is 1000, find count after 12 hours.Strategy Hint: N(t)=N0⋅2t/3.N(12)=1000⋅24=1000⋅16=1600016,000 Q7: Determine if f(x)=(32)x represents growth or decay.Strategy Hint: Base = 2/3≈0.667<1.Decay.Decay Q8: Compute (8)−2/3.Strategy Hint: 8−2/3=82/31=(38)21=221=41.41 Q9: If f(x)=2x+1, find f(3).f(3)=24=1616 Q10: The half-life of a drug in the body is 6 hours. If a patient takes 200mg, how much remains after 24 hours?N(24)=200⋅(1/2)24/6=200⋅(1/2)4=200⋅1/16=12.512.5 mg Q11: Write 2⋅32 in the form 2x.2=21/2, 32=21/3. Product: 21/2+1/3=25/625/6 Q12: If a function fails the horizontal line test, does it pass the vertical line test?Strategy Hint: These tests check different things.HLT checks injectivity. VLT checks if it's a function. A function can fail HLT (not injective) but always passes VLT.Yes — it’s still a function but not injective
🔗 Cross-References
- Next topic: Composite and Inverse Functions
- Related: Logarithms — the inverse of exponentials
- Across courses: BSMA1003 Maths 2 (exponential functions in differential equations); BSMA1002 Stats 1 (exponential distributions, growth models) Join Discord Previous4.0 Polynomial OperationsNext5.2 Composite & Inverse Functions