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Limits of Functions

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Limits of Functions

🎯 Learning Objectives

By the end of this topic, you will be able to:
  1. Define the limit of a function at a point
  2. Compute one-sided limits and determine when a two-sided limit exists
  3. Evaluate limits using algebraic manipulation, factoring, rationalization
  4. Apply standard limit results: sinxx\frac{\sin x}{x}, ex1x\frac{e^x-1}{x}, ln(1+x)x\frac{\ln(1+x)}{x}
  5. Recognize and resolve indeterminate forms using L'Hôpital's rule

📋 Prerequisites


📖 Core Content

11.1 Intuition: Approaching a Point

What happens to f(x)=x2f(x) = x^2 as xx gets closer and closer to 33? The output approaches 99. We write limx3x2=9\lim_{x \to 3} x^2 = 9. The limit describes the trend of f(x)f(x) near x=ax = a, regardless of whether f(a)f(a) is defined. This is crucial for understanding derivatives and continuity.
💡 Why this matters: Limits are the foundation of calculus. Derivatives = limits of difference quotients. Integrals = limits of Riemann sums. Everything in calculus rests on limits.

11.2 Definition

limxaf(x)=L\lim_{x \to a} f(x) = L
Means: as xx gets arbitrarily close to aa (from either side), f(x)f(x) gets arbitrarily close to LL.

11.2.1 One-Sided Limits

  • Left-hand limit: limxaf(x)\lim_{x \to a^-} f(x) — approach aa from below (smaller values)
  • Right-hand limit: limxa+f(x)\lim_{x \to a^+} f(x) — approach aa from above (larger values) Two-sided limit exists iff both one-sided limits exist and are equal:
limxaf(x)=L    limxaf(x)=limxa+f(x)=L\lim_{x \to a} f(x) = L \iff \lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x) = L
(Diagram)

11.3 Properties of Limits

If limxaf(x)=L\lim_{x \to a} f(x) = L and limxag(x)=M\lim_{x \to a} g(x) = M:
PropertyFormula
Sumlim[f(x)+g(x)]=L+M\lim[f(x) + g(x)] = L + M
Differencelim[f(x)g(x)]=LM\lim[f(x) - g(x)] = L - M
Productlim[f(x)g(x)]=LM\lim[f(x) \cdot g(x)] = L \cdot M
Quotientlimf(x)/g(x)=L/M\lim f(x)/g(x) = L/M (if M0M \neq 0 )
Constant multiplelimcf(x)=cL\lim c \cdot f(x) = cL
Powerlim[f(x)]n=Ln\lim [f(x)]^n = L^n
Rootlimf(x)n=Ln\lim \sqrt[n]{f(x)} = \sqrt[n]{L} (if L0L \geq 0 for even nn )

11.4 Standard Limits (Very Important!)

FormulaNotes
limx0sinxx=1\displaystyle \lim_{x \to 0} \frac{\sin x}{x} = 1xx in radians
limx01cosxx=0\displaystyle \lim_{x \to 0} \frac{1 - \cos x}{x} = 0
limx0ex1x=1\displaystyle \lim_{x \to 0} \frac{e^x - 1}{x} = 1
limx0ln(1+x)x=1\displaystyle \lim_{x \to 0} \frac{\ln(1+x)}{x} = 1
limx(1+1x)x=e\displaystyle \lim_{x \to \infty} \left(1 + \frac{1}{x}\right)^x = e
limx0(1+x)1/x=e\displaystyle \lim_{x \to 0} (1 + x)^{1/x} = eSame as above

11.5 Evaluation Techniques

11.5.1 Direct Substitution

If ff is continuous at aa, limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a). Works for polynomials, rational functions (where denominator ≠ 0), trig functions, exponentials.

11.5.2 Factoring

When substitution gives 0/00/0, factor and cancel. Example: limx2x24x2\lim_{x \to 2} \frac{x^2 - 4}{x - 2}
limx2(x2)(x+2)x2=limx2(x+2)=4\lim_{x \to 2} \frac{(x-2)(x+2)}{x-2} = \lim_{x \to 2} (x+2) = 4

11.5.3 Rationalization

When radicals cause 0/00/0, multiply by conjugate. Example: limx0x+11x\lim_{x \to 0} \frac{\sqrt{x+1} - 1}{x}
limx0(x+11)(x+1+1)x(x+1+1)=limx0xx(x+1+1)=limx01x+1+1=12\lim_{x \to 0} \frac{(\sqrt{x+1}-1)(\sqrt{x+1}+1)}{x(\sqrt{x+1}+1)} = \lim_{x \to 0} \frac{x}{x(\sqrt{x+1}+1)} = \lim_{x \to 0} \frac{1}{\sqrt{x+1}+1} = \frac{1}{2}

11.5.4 Limits at Infinity

Divide numerator and denominator by highest power of xx. Example: limx3x2+2x4x21=34\lim_{x \to \infty} \frac{3x^2 + 2x}{4x^2 - 1} = \frac{3}{4}

11.6 Indeterminate Forms

FormExample
0/00/0x24x2\frac{x^2-4}{x-2} at x=2x=2
/\infty/\inftyx2+1x1\frac{x^2+1}{x-1} as xx\to\infty
00 \cdot \inftyxlnxx \cdot \ln x as x0+x\to 0^+
\infty - \inftyx+1x\sqrt{x+1} - \sqrt{x} as xx\to\infty
000^0xxx^x as x0+x\to 0^+
11^\infty(1+1/x)x(1+1/x)^x as xx\to\infty
0\infty^0x1/xx^{1/x} as xx\to\infty

11.7 L'Hôpital's Rule

If limxaf(x)/g(x)\lim_{x \to a} f(x)/g(x) is 0/00/0 or /\infty/\infty, and limf(x)/g(x)\lim f'(x)/g'(x) exists:
limxaf(x)g(x)=limxaf(x)g(x)\lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f'(x)}{g'(x)}
Important: Only applies to 0/00/0 or /\infty/\infty forms. Must differentiate numerator and denominator separately (not quotient rule!).

Worked Examples

Example 4.1: limx0sinxx\lim_{x \to 0} \frac{\sin x}{x} (using L'Hôpital)
limx0sinxx=limx0cosx1=1\lim_{x \to 0} \frac{\sin x}{x} = \lim_{x \to 0} \frac{\cos x}{1} = 1
Example 4.2: limxx2ex\lim_{x \to \infty} \frac{x^2}{e^x}
limxx2ex=limx2xex=limx2ex=0\lim_{x \to \infty} \frac{x^2}{e^x} = \lim_{x \to \infty} \frac{2x}{e^x} = \lim_{x \to \infty} \frac{2}{e^x} = 0
Example 4.3: limx0ex1xx2\lim_{x \to 0} \frac{e^x - 1 - x}{x^2}
limx0ex1xx2=limx0ex12x=limx0ex2=12\lim_{x \to 0} \frac{e^x - 1 - x}{x^2} = \lim_{x \to 0} \frac{e^x - 1}{2x} = \lim_{x \to 0} \frac{e^x}{2} = \frac{1}{2}

📐 Key Formulas — Summary Table

FormTechnique
0/00/0 (polynomial)Factor and cancel
0/00/0 (radical)Rationalize
/\infty/\inftyDivide by highest power
0/00/0 or /\infty/\inftyL'Hôpital's rule
00 \cdot \inftyRewrite as 0/00/0 or /\infty/\infty
\infty - \inftyCommon denominator or conjugate
11^\inftyUse lim=elim(f(x)1)g(x)\lim = e^{\lim (f(x)-1)g(x)}
Standard limit: limx0sinxx=1, limx0ex1x=1, limx0ln(1+x)x=1\boxed{\text{Standard limit: } \lim_{x\to 0} \frac{\sin x}{x} = 1,\ \lim_{x\to 0} \frac{e^x-1}{x} = 1,\ \lim_{x\to 0} \frac{\ln(1+x)}{x} = 1}

⚠️ Common Pitfalls

Pitfall 1: Applying L'Hôpital to Non-Indeterminate Forms

limx1x2x=1\lim_{x \to 1} \frac{x^2}{x} = 1 directly. Using L'Hôpital: 2x1=2\frac{2x}{1} = 2 — WRONG! The form was 1/11/1, not 0/00/0 or /\infty/\infty.

Pitfall 2: Confusing One-Sided Limits with Two-Sided

If limxaf(x)limxa+f(x)\lim_{x \to a^-} f(x) \neq \lim_{x \to a^+} f(x), then limxaf(x)\lim_{x \to a} f(x) does NOT exist.

Pitfall 3: Forgetting That sinx/x\sin x/x Requires Radians

The limit limx0sinxx=1\lim_{x\to 0} \frac{\sin x}{x} = 1 only holds when xx is in radians.

📝 Practice Questions

Q1: Find limx3(2x+1)\lim_{x \to 3} (2x + 1).
Direct substitution: 2(3)+1=72(3) + 1 = 7
7\boxed{7} Q2: Find limx2x23x+2x2\lim_{x \to 2} \frac{x^2 - 3x + 2}{x-2}.
Factor: (x1)(x2)x2=x11\frac{(x-1)(x-2)}{x-2} = x-1 \to 1
1\boxed{1} Q3: Find limx04+x2x\lim_{x \to 0} \frac{\sqrt{4+x} - 2}{x}.
Rationalize: (4+x2)(4+x+2)x(4+x+2)=xx(4+x+2)=14+x+214\frac{(\sqrt{4+x} - 2)(\sqrt{4+x}+2)}{x(\sqrt{4+x}+2)} = \frac{x}{x(\sqrt{4+x}+2)} = \frac{1}{\sqrt{4+x}+2} \to \frac{1}{4}
14\boxed{\frac{1}{4}} Q4: Find limx5x23x+12x2+7\lim_{x \to \infty} \frac{5x^2 - 3x + 1}{2x^2 + 7}.
Divide by x2x^2: 53/x+1/x22+7/x252\frac{5 - 3/x + 1/x^2}{2 + 7/x^2} \to \frac{5}{2}
52\boxed{\frac{5}{2}} Q5: Find limx0sin3xx\lim_{x \to 0} \frac{\sin 3x}{x}.
sin3xx=3sin3x3x31=3\frac{\sin 3x}{x} = 3 \cdot \frac{\sin 3x}{3x} \to 3 \cdot 1 = 3
3\boxed{3} Q6: Find limx01cosxx2\lim_{x \to 0} \frac{1 - \cos x}{x^2}.
=limx0sinx2x=121=12= \lim_{x\to 0} \frac{\sin x}{2x} = \frac{1}{2} \cdot 1 = \frac{1}{2}
12\boxed{\frac{1}{2}} Q7: Find limx0e2x1x\lim_{x \to 0} \frac{e^{2x} - 1}{x}.
=2limx0e2x12x=21=2= 2 \cdot \lim_{x\to 0} \frac{e^{2x} - 1}{2x} = 2 \cdot 1 = 2
2\boxed{2} Q8: Evaluate limx0x2sinx\lim_{x \to 0} \frac{x^2}{\sin x}.
=limx0xsinxx=10=0= \lim_{x\to 0} \frac{x}{\sin x} \cdot x = 1 \cdot 0 = 0
0\boxed{0} Q9: Find limx1x31x1\lim_{x \to 1} \frac{x^3 - 1}{x - 1}.
Factor: (x1)(x2+x+1)x1=x2+x+13\frac{(x-1)(x^2+x+1)}{x-1} = x^2 + x + 1 \to 3
3\boxed{3} Q10: Find limx0+xlnx\lim_{x \to 0^+} x \ln x.
Rewrite as lnx1/x\frac{\ln x}{1/x}: /-\infty/\infty form. L'Hôpital: 1/x1/x2=x0\frac{1/x}{-1/x^2} = -x \to 0
0\boxed{0} Q11: Find limx0ex1sinx\lim_{x \to 0} \frac{e^x - 1}{\sin x}.
L'Hôpital: excosx11=1\frac{e^x}{\cos x} \to \frac{1}{1} = 1
1\boxed{1} Q12: Find limx0(1+2x)1/x\lim_{x \to 0} (1 + 2x)^{1/x}.
This is 11^\infty form. limx0(1+2x)1/x=elimx0ln(1+2x)x=elimx021+2x=e2\lim_{x\to 0} (1+2x)^{1/x} = e^{\lim_{x\to 0} \frac{\ln(1+2x)}{x}} = e^{\lim_{x\to 0} \frac{2}{1+2x}} = e^{2}
e2\boxed{e^2}

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