Quiz 2
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Mathematics I · Week 3 — Quadratic functions

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6 min read
2026-08-16

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Week 3 — quadratic functions

Quiz 2 scope: Weeks 1–8 per IITM May 2026 foundation courses. Source baseline: IITM BS admissions important-dates calendar · May 2026 cycle. Times on assessments are operational conventions — verify hall ticket.

Week map

Standard form → factoring/roots → vertex → discriminant → graph features

Classify → Represent → Execute → Trap-check

  • Recognize: Ask: What does D=0D=0 imply about the graph?
  • Procedure: Look for two numbers that multiply to acac and add to bb when a=1a=1. Set each factor to zero. Verify by substitution. If monic and prime over integers, state that and switch to formula.
  • Variations / traps: Watch for: Sign error in h=b/(2a)h = -b/(2a) when bb is negative.

Formula chain (compressed)

f(x)=ax²+bx+c → roots via factor/formula → Δ=b²−4ac → vertex xᵥ=−b/(2a).
  1. Standard formf(x) = ax² + bx + c, a≠0 — identify quadratic
  2. DiscriminantΔ = b² − 4ac — count real roots
  3. Quadratic formulax = (−b ± √Δ)/(2a) — factoring hard
  4. Vertex xxᵥ = −b/(2a) — turning point
  5. Openinga>0 cup (min), a<0 cap (max) — graph sketch

Deep study

Mathematics I · Week 3 — Quadratic functions

Parabolas link algebra (polynomial degree 2), graphs (vertex and symmetry), and root-finding.

Week map

Standard form ax2+bx+cax^2+bx+c → graph shape → factoring and roots → quadratic formula → vertex and axis → discriminant → parameter problems.

Quadratic notation

  • f(x)=ax2+bx+cf(x) = ax^2 + bx + c → standard quadratic → a0a \neq 0f(x)=2x24x+1f(x) = 2x^2 - 4x + 1.
  • aa → leading coefficient → sign sets cup up (a>0a>0) or down (a<0a<0).
  • Root / zero → input where f(x)=0f(x)=0 → solve ax2+bx+c=0ax^2+bx+c=0.
  • h=b2ah = -\frac{b}{2a}xx-coordinate of vertex → axis of symmetry vertical line x=hx=h.
  • D=b24acD = b^2 - 4ac → discriminant → classifies real roots.

Vertex form

f(x)=a(xh)2+kf(x) = a(x-h)^2 + k → vertex (h,k)(h,k) → graph shifts hh horizontal, kk vertical.
Mini-example: f(x)=3(x2)25f(x) = 3(x-2)^2 - 5 has vertex (2,5)(2,-5), opens upward (a=3>0a=3>0).

Roots and the discriminant

DDReal roots
D>0D > 0two distinct
D=0D = 0one repeated (touch axis)
D<0D < 0none (no horizontal crossing)
Quadratic formula: x=b±D2ax = \frac{-b \pm \sqrt{D}}{2a} when solving ax2+bx+c=0ax^2+bx+c=0.
Mini-example: x25x+6=0x^2 - 5x + 6 = 0. Factor (x2)(x3)=0(x-2)(x-3)=0 → roots 2,32,3. Check D=2524=1>0D = 25-24 = 1 > 0.

Factoring strategy (monic a=1a=1)

Find integers p,qp,q with pq=cpq = c and p+q=bp+q = b for x2+bx+cx^2+bx+c.
x2+x12x^2 + x - 12: need product 12-12, sum 1144 and 3-3(x+4)(x3)(x+4)(x-3).
If no integer pair works, use formula or completing the square.

Completing the square sketch

x2+6x+1=(x2+6x+9)9+1=(x+3)28x^2 + 6x + 1 = (x^2+6x+9) - 9 + 1 = (x+3)^2 - 8. Vertex (3,8)(-3,-8).

Graph features

  • Axis of symmetry: x=hx = h.
  • yy-intercept: f(0)=cf(0) = c.
  • Direction: min value at vertex if a>0a>0; max if a<0a<0.
  • Width: larger a|a| → narrower parabola.

Pattern families

Easy — Factor and solve

  • Monic quadratics with integer roots.
  • Read vertex from (xh)2+k(x-h)^2+k when given.
  • State yy-intercept from cc.

Medium — Vertex and transformation

  • Convert standard to vertex form by completing square or formula for h,kh,k.
  • Given roots, write quadratic in factored form a(xr1)(xr2)a(x-r_1)(x-r_2).
  • Use symmetry: roots equidistant from axis at hh.

Hard — Discriminant parameters

  • Find values of kk so x2+kx+9=0x^2 + kx + 9 = 0 has exactly one real root → D=0D=0.
  • Inequalities on DD for “no real roots” or “two real roots”.
  • Word constraints linking vertex height to domain (e.g. minimum cost).

Worked mini-examples

Example 1 — Factoring. 2x28x+6=02x^2 - 8x + 6 = 0. Divide 2: x24x+3=0x^2 - 4x + 3 = 0(x1)(x3)=0(x-1)(x-3)=0x=1,3x=1,3.
Example 2 — Vertex. f(x)=x2+4x+1f(x) = -x^2 + 4x + 1. h=4/(21)=2h = -4/(2\cdot -1) = 2. f(2)=4+8+1=5f(2) = -4+8+1 = 5. Vertex (2,5)(2,5), max (since a=1a=-1).
Example 3 — Discriminant. 3x22x+k=03x^2 - 2x + k = 0 has no real roots when D=412k<0D = 4 - 12k < 0k>13k > \frac{1}{3}.
Example 4 — From roots. Roots 2-2 and 55: f(x)=a(x+2)(x5)f(x) = a(x+2)(x-5). If a=1a=1, f(x)=x23x10f(x) = x^2 - 3x - 10. c=10c = -10 is yy-intercept.

Traps

  • Sign error in h=b/(2a)h = -b/(2a) when bb negative.
  • Vertex (h,k)(h,k) confused with roots (zeros on xx-axis).
  • Forgetting aa when using formula: divide by 2a2a, not 2.
  • D=0D=0 means one repeated root, not “no roots”.
  • Opening direction from sign of aa, not cc.

Diagnostic (try yourself)

  1. Solve x2+7x+10=0x^2 + 7x + 10 = 0 by factoring.
  2. Find the vertex and axis of symmetry of f(x)=2x212x+5f(x) = 2x^2 - 12x + 5.
  3. For what values of mm does x2+mx+16=0x^2 + mx + 16 = 0 have exactly one real solution?
  4. A parabola has roots at x=1x = 1 and x=9x = 9 and passes through (0,18)(0, 18). Write f(x)f(x) in standard form.
  5. Without fully solving, how many real roots does 2x2+3x7=02x^2 + 3x - 7 = 0 have? Use the discriminant.

ChatGPT prep archive

Archived import for extra depth — complements the notes above, not official IITM material.

Core concepts

  • Standard form f(x)=ax2+bx+cf(x) = ax^2 + bx + c; parabola opens up if a>0a>0, down if a<0a<0.
  • Roots from factoring, completing the square, or quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2-4ac}}{2a}.
  • Vertex (h,k)(h,k) from h=b/(2a)h = -b/(2a), k=f(h)k = f(h); vertex form a(xh)2+ka(x-h)^2 + k.
  • Discriminant D=b24acD = b^2 - 4ac: positive two real roots, zero one repeated, negative no real roots.

Notation & vocabulary

FormUse
ax2+bx+cax^2+bx+ccoefficients, discriminant
a(xh)2+ka(x-h)^2+kvertex, transformations
D=b24acD=b^2-4acroot count (real)

Pattern families

Easy — Factor simple quadratics

Look for two numbers that multiply to acac and add to bb when a=1a=1. Set each factor to zero. Verify by substitution. If monic and prime over integers, state that and switch to formula.

Medium — Vertex and axis

Compute h=b/(2a)h = -b/(2a) and evaluate f(h)f(h) for vertex. Axis of symmetry is vertical line x=hx=h. Compare vertex yy-value with roots to sketch direction and width from aa.

Hard — Parameter in discriminant

Set discriminant condition for desired root type: D>0D>0, D=0D=0, or D<0D<0. Solve inequality for parameter kk. Boundary cases D=0D=0 often mark transition points—test them separately.
Drill these on the pattern atlas — filter to week 3.

Traps

  • Sign error in h=b/(2a)h = -b/(2a) when bb is negative.
  • Confusing vertex (h,k)(h,k) with roots.
  • Using quadratic formula without checking for factorization first on easy integers.
  • Assuming two roots always means positive discriminant without checking reality.

Retrieval prompts

  1. What does D=0D=0 imply about the graph?
  2. How do you convert f(x)=x26x+5f(x)=x^2-6x+5 to vertex form?
  3. Which direction opens for f(x)=2x2+3xf(x)=-2x^2+3x?

Practice loop

  1. Read Deep study (if present) or core concepts once.
  2. Recite the formula chain without looking.
  3. Open one easy pattern on the interactive atlas for week 3.
  4. Attempt without solutions; mark studied after an honest try.
  5. Say one trap aloud before closing the tab.
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