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Mathematics I · Week 6 — Logarithmic functions
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Mathematics I · Week 6 — Logarithmic functions
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2026-08-16
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Week 6 — logarithmic functions
Quiz 2 scope: Weeks 1–8 per IITM May 2026 foundation courses. Source baseline: IITM BS admissions important-dates calendar · May 2026 cycle. Times on assessments are operational conventions — verify hall ticket.
Week map
Exp inverse → log definition → laws → solve → domain restrictions
Classify → Represent → Execute → Trap-check
- Recognize: Ask: What does log28 ask in words?
- Procedure: Rewrite as exponent question: "what power of base gives this number?" Use loga1=0, logaa=1. For base 10 or e, connect to familiar values.
- Variations / traps: Watch for: Using log(x+y)=logx+logy (false).
Formula chain (compressed)
log = inverse of exp → log laws → change of base → solve log equations.
- Definition —
y=log_a(x) ⇔ a^y=x— a>0, a≠1, x>0 - Product —
log(ab)=log a + log b— same base - Quotient —
log(a/b)=log a − log b— same base - Power —
log(a^k)=k log a— pull exponent out - Change of base —
log_a b = log_c b / log_c a— calculator base
Open interactive formula desk · Week 6 tab.
Deep study
Mathematics I · Week 6 — Logarithms
Deep study for Quiz 2 week 6. Logarithm is the inverse operation of exponentiation — every log question hides an exponent question.
Week map
Log as inverse of exp → definition and domain → log laws → change of base → solve log equations → check solutions.
Logarithm notation
- logax → “log base a of x” → the exponent y such that ay=x → requires a>0, a=1, x>0.
- lnx → natural log → base e → lnx=logex.
- log10x or logx → common log (context-dependent).
Mini-example: log28=3 because 23=8. log51=0 because 50=1. log33=1.
Key identities
- alogax=x for x>0.
- loga(ax)=x for all real x.
- loga1=0; logaa=1.
Log laws
- Product: loga(xy)=logax+logay.
- Quotient: loga(x/y)=logax−logay.
- Power: loga(xn)=nlogax.
- Change of base: logax=logbalogbx for any valid base b.
Mini-example: log2(16⋅4)=log216+log24=4+2=6. Check: 26=64=16⋅4.
Graph features
- Domain (0,∞); vertical asymptote at x=0.
- Passes through (1,0) and (a,1).
- Reflection of y=ax over y=x.
Pattern families
Easy — Evaluate simple logs
Rewrite as “what power of base gives this number?” Use loga1=0, logaa=1. Connect base-10 and natural logs to familiar values.
Medium — Apply log laws
Expand or condense expressions. Split products into sums; bring exponents down. Change base to evaluate unfamiliar logs.
Hard — Solve log and exponential equations
Isolate log or exponent; convert between forms. Always check solutions in original equation — extraneous values appear when domain violated.
Worked mini-examples
Example 1 — Definition.
log381=? → 3y=81=34 → answer 4.
Example 2 — Product law.
log1050+log102=log10100=2.
Example 3 — Power law.
log2(x5)=5log2x.
Example 4 — Change of base.
log48=ln4ln8=2ln23ln2=3/2.
Example 5 — Solve.
log2(x−1)=3 → x−1=23=8 → x=9. Check: log28=3 ✓. Domain requires x−1>0, so x>1 — satisfied.
Traps
- Taking log of negative number or zero — undefined.
- Using log(x+y)=logx+logy — false; product law only.
- Forgetting 0!-style edge: loga1=0, not undefined.
- Dividing logs incorrectly: logx/logy=log(x/y).
- Accepting solution that makes log argument ≤0.
Diagnostic (try yourself)
-
Evaluate log5125 and log3(1/9).
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Expand log2(8x3) using log laws.
-
Use change of base to express log84 as a fraction.
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Solve log10(x)=2. State the domain condition.
-
True or false: ln(e5)=5? What is ln1?
ChatGPT prep archive
Archived import for extra depth — complements the notes above, not official IITM material.
Core concepts
- Definition: y=logax means ay=x, with a>0, a=1, x>0.
- Common laws: loga(xy)=logax+logay; loga(xn)=nlogax; change of base.
- Graph: reflection of exponential over y=x; vertical asymptote x=0.
- Solving: isolate log or exponent; check solutions in original domain.
Notation & vocabulary
| Law | Form |
|---|---|
| Product | log(xy)=logx+logy |
| Power | log(xn)=nlogx |
| Change of base | logax=logbalogbx |
Pattern families
Easy — Evaluate simple logs
Rewrite as exponent question: "what power of base gives this number?" Use loga1=0, logaa=1. For base 10 or e, connect to familiar values.
Medium — Expand or condense
Apply product and power rules in the direction requested. Factor arguments before splitting sums. Condense only when arguments share the same base.
Hard — Log equation with domain
Combine logs to single logarithm or exponentiate both sides. Solve resulting equation. Discard extraneous values that make any original log argument nonpositive.
Drill these on the pattern atlas — filter to week 6.
Traps
- Using log(x+y)=logx+logy (false).
- Forgetting x>0 in logx.
- Exponentiating without applying to entire side.
- Change-of-base with inverted fraction.
Retrieval prompts
- What does log28 ask in words?
- Why must log arguments be positive?
- How do you solve 2x=10 using logs?
Practice loop
- Read Deep study (if present) or core concepts once.
- Recite the formula chain without looking.
- Open one easy pattern on the interactive atlas for week 6.
- Attempt without solutions; mark studied after an honest try.
- Say one trap aloud before closing the tab.