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Mathematics I · Week 7 — Sequences, limits & continuity
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Mathematics I · Week 7 — Sequences, limits & continuity
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6 min read
2026-08-16
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Now · Week map
Week 7 — sequences, limits & continuity
Quiz 2 scope: Weeks 1–8 per IITM May 2026 foundation courses. Source baseline: IITM BS admissions important-dates calendar · May 2026 cycle. Times on assessments are operational conventions — verify hall ticket.
Week map
Sequence terms → limit intuition → one-sided limits → continuity at a point
Classify → Represent → Execute → Trap-check
- Recognize: Ask: What three conditions define continuity at a?
- Procedure: Write first several terms from formula. Describe trend: increasing, decreasing, bounded. Guess limit by table or simplifying an for large n (e.g. divide numerator and denominator by highest power).
- Variations / traps: Watch for: Assuming limit equals function value without checking.
Formula chain (compressed)
sequence aₙ → limit L → one-sided limits → continuity at a point.
- Sequence limit —
aₙ → L as n→∞— terms approach L - Left / right limit —
lim_{x→a⁻} f, lim_{x→a⁺} f— piecewise or endpoints - Limit exists —
left = right = L— two-sided limit at a - Continuity —
lim_{x→a} f(x) = f(a)— no jump/hole at a - Standard limits —
lim sin x/x = 1 (x→0)— squeeze / known forms
Open interactive formula desk · Week 7 tab.
Deep study
Mathematics I · Week 7 — Limits and continuity
Deep study for Quiz 2 week 7. Limits describe approaching behavior; continuity requires the approach to match the actual value.
Week map
Sequence terms → limit intuition → one-sided limits → two-sided limit → continuity at a point → types of discontinuity.
Limit notation
- limx→af(x)=L → “limit of f(x) as x approaches a is L” → value f tends toward near a, not necessarily at a.
- limx→a−f(x) → left-hand limit → approach from values less than a.
- limx→a+f(x) → right-hand limit → approach from values greater than a.
- limx→af(x) exists iff left and right limits exist and are equal.
Mini-example: f(x)=x−1x2−1 for x=1. Near x=1: factor to x+1, so limx→1f(x)=2, even though f(1) is undefined.
Sequence limits
- limn→∞an=L → terms an get arbitrarily close to L as n grows.
- For rational sequences, divide numerator and denominator by highest power of n to guess limit.
Mini-example: an=n+23n+1. Divide top and bottom by n: 1+2/n3+1/n→3 as n→∞.
Continuity notation
- Continuous at a: limx→af(x)=f(a) — limit exists, function defined, and they agree.
- Removable discontinuity: limit exists but f(a) missing or wrong — “hole” in graph.
- Jump discontinuity: left and right limits exist but differ.
- Infinite discontinuity: limit blows up to ±∞.
Mini-example: f(x)=∣x∣/x at x=0. Left limit −1, right limit +1 — jump discontinuity.
Pattern families
Easy — Sequence pattern
Write first several terms from formula. Describe trend. Guess limit by table or simplifying for large n.
Medium — One-sided and two-sided limits
Evaluate limits from graphs. Identify left vs right behavior at breakpoints, absolute value corners, piecewise joins.
Hard — Continuity classification
Decide if function is continuous at a point. Identify discontinuity type. State what value would make function continuous (removable case).
Worked mini-examples
Example 1 — Direct substitution.
limx→3(2x+5)=11 — polynomial, no issue.
Example 2 — Cancel factor.
limx→2x−2x2−4=limx→2(x+2)=4.
Example 3 — One-sided.
f(x)={x+1x2x<0x≥0. Left at 0: 1; right at 0: 0. Two-sided limit does not exist.
Example 4 — Sequence.
an=n1→0 as n→∞.
Example 5 — Removable.
f(x)=xsinx for x=0, f(0)=0. limx→0xsinx=1=f(0) — removable if redefine f(0)=1.
Traps
- Assuming limx→af(x)=f(a) without checking.
- Ignoring one-sided limits at piecewise boundaries.
- Thinking limit at infinity means function equals that value.
- Canceling (x−a) without noting hole at x=a.
- Sequence limit confused with finite term value.
Diagnostic (try yourself)
-
Find limx→5(x2−3x).
-
Evaluate limx→1x−1x2−1.
-
For f(x)=x∣x∣, what are the left and right limits at x=0?
-
Sequence an=n+52n: what value does an approach as n→∞?
-
A function has limx→2f(x)=7 but f(2)=3. Is it continuous at 2? What type of issue is this?
ChatGPT prep archive
Archived import for extra depth — complements the notes above, not official IITM material.
Core concepts
- Sequence limit: terms an approach L as n grows; not every sequence converges.
- Function limit at a: value approached as x→a (may differ from f(a)).
- One-sided: limx→a−f(x) and limx→a+f(x).
- Continuous at a: limx→af(x)=f(a); all three must agree.
Notation & vocabulary
| Term | Meaning |
|---|---|
| limn→∞an=L | sequence converges to L |
| limx→af(x) | two-sided limit |
| Discontinuity | limit exists but =f(a), or limit fails |
Pattern families
Easy — Sequence pattern
Write first several terms from formula. Describe trend: increasing, decreasing, bounded. Guess limit by table or simplifying an for large n (e.g. divide numerator and denominator by highest power).
Medium — Limit by algebra
Factor rational functions to cancel hole-causing terms. For piecewise functions, match one-sided limits at junction. If left = right, two-sided limit does not exist.
Hard — Continuity classification
Evaluate f(a), left limit, right limit. Removable if limits agree but f(a) wrong or missing. Jump if one-sided limits differ. Infinite if unbounded approach.
Drill these on the pattern atlas — filter to week 7.
Traps
- Assuming limit equals function value without checking.
- Ignoring one-sided limits at piecewise knots.
- Sequence index n vs function variable x.
- Thinking oscillation implies convergence.
Retrieval prompts
- What three conditions define continuity at a?
- When does a two-sided limit fail to exist?
- How do you find limn→∞n3n+1?
Practice loop
- Read Deep study (if present) or core concepts once.
- Recite the formula chain without looking.
- Open one easy pattern on the interactive atlas for week 7.
- Attempt without solutions; mark studied after an honest try.
- Say one trap aloud before closing the tab.