Quiz 2
Registry Synced

maths1-week7

613 words
3 min read

Reading compass

Now · Week map

Deep study for Quiz 2 week 7. Limits describe approaching behavior; continuity requires the approach to match the actual value.

Week map

Sequence terms → limit intuition → one-sided limits → two-sided limit → continuity at a point → types of discontinuity.

Limit notation

  • limxaf(x)=L\lim_{x \to a} f(x) = L → “limit of f(x)f(x) as xx approaches aa is LL” → value ff tends toward near aa, not necessarily at aa.
  • limxaf(x)\lim_{x \to a^-} f(x) → left-hand limit → approach from values less than aa.
  • limxa+f(x)\lim_{x \to a^+} f(x) → right-hand limit → approach from values greater than aa.
  • limxaf(x)\lim_{x \to a} f(x) exists iff left and right limits exist and are equal.
Mini-example: f(x)=x21x1f(x) = \frac{x^2 - 1}{x - 1} for x1x \neq 1. Near x=1x = 1: factor to x+1x + 1, so limx1f(x)=2\lim_{x \to 1} f(x) = 2, even though f(1)f(1) is undefined.

Sequence limits

  • limnan=L\lim_{n \to \infty} a_n = L → terms ana_n get arbitrarily close to LL as nn grows.
  • For rational sequences, divide numerator and denominator by highest power of nn to guess limit.
Mini-example: an=3n+1n+2a_n = \frac{3n + 1}{n + 2}. Divide top and bottom by nn: 3+1/n1+2/n3\frac{3 + 1/n}{1 + 2/n} \to 3 as nn \to \infty.

Continuity notation

  • Continuous at aa: limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a) — limit exists, function defined, and they agree.
  • Removable discontinuity: limit exists but f(a)f(a) missing or wrong — “hole” in graph.
  • Jump discontinuity: left and right limits exist but differ.
  • Infinite discontinuity: limit blows up to ±\pm\infty.
Mini-example: f(x)=x/xf(x) = |x|/x at x=0x = 0. Left limit 1-1, right limit +1+1 — jump discontinuity.

Pattern families

Easy — Sequence pattern

Write first several terms from formula. Describe trend. Guess limit by table or simplifying for large nn.

Medium — One-sided and two-sided limits

Evaluate limits from graphs. Identify left vs right behavior at breakpoints, absolute value corners, piecewise joins.

Hard — Continuity classification

Decide if function is continuous at a point. Identify discontinuity type. State what value would make function continuous (removable case).

Worked mini-examples

Example 1 — Direct substitution.
limx3(2x+5)=11\lim_{x \to 3} (2x + 5) = 11 — polynomial, no issue.
Example 2 — Cancel factor.
limx2x24x2=limx2(x+2)=4\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = \lim_{x \to 2} (x + 2) = 4.
Example 3 — One-sided.
f(x)={x+1x<0x2x0f(x) = \begin{cases} x+1 & x < 0 \\ x^2 & x \geq 0 \end{cases}. Left at 0: 11; right at 0: 00. Two-sided limit does not exist.
Example 4 — Sequence.
an=1n0a_n = \frac{1}{n} \to 0 as nn \to \infty.
Example 5 — Removable.
f(x)=sinxxf(x) = \frac{\sin x}{x} for x0x \neq 0, f(0)=0f(0) = 0. limx0sinxx=1f(0)\lim_{x \to 0} \frac{\sin x}{x} = 1 \neq f(0) — removable if redefine f(0)=1f(0) = 1.

Traps

  • Assuming limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a) without checking.
  • Ignoring one-sided limits at piecewise boundaries.
  • Thinking limit at infinity means function equals that value.
  • Canceling (xa)(x - a) without noting hole at x=ax = a.
  • Sequence limit confused with finite term value.

Diagnostic (try yourself)

  1. Find limx5(x23x)\lim_{x \to 5} (x^2 - 3x).
  2. Evaluate limx1x21x1\lim_{x \to 1} \frac{x^2 - 1}{x - 1}.
  3. For f(x)=xxf(x) = \frac{|x|}{x}, what are the left and right limits at x=0x = 0?
  4. Sequence an=2nn+5a_n = \frac{2n}{n + 5}: what value does ana_n approach as nn \to \infty?
  5. A function has limx2f(x)=7\lim_{x \to 2} f(x) = 7 but f(2)=3f(2) = 3. Is it continuous at 2? What type of issue is this?
Document outline

Keep your place and jump directly to a heading.

Table of Contents
System Normal // Awaiting Context

Intelligence Hub

Navigate the knowledge graph to generate context. The Hub adapts dynamically to surface backlinks, related notes, and metadata insights.