Quiz 2
Registry Synced

stats1-week6

433 words
2 min read

Reading compass

Now · Week map

Deep study for Quiz 2 week 6. Permutations count ordered arrangements; combinations count unordered selections.

Week map

Order matters? → permutation → order irrelevant? → combination → formulas → complement counting → word-problem translation.

Permutation notation

  • P(n,r)P(n, r) or nPr{}^nP_r → permutations of rr items chosen from nn distinct → order matters.
  • Formula: P(n,r)=n!(nr)!P(n,r) = \dfrac{n!}{(n-r)!}.
  • Special case: P(n,n)=n!P(n,n) = n! — arrange all nn.
Mini-example: Top 2 finishers from 5 runners. Order matters (gold vs silver): P(5,2)=5×4=20P(5,2) = 5 \times 4 = 20.

Combination notation

  • C(n,r)C(n, r) or (nr)\binom{n}{r} → combinations — choose rr from nnorder does not matter.
  • Formula: C(n,r)=n!r!(nr)!C(n,r) = \dfrac{n!}{r!(n-r)!}.
  • (n0)=1\binom{n}{0} = 1; (nn)=1\binom{n}{n} = 1.
Mini-example: Choose 2 toppings from 5 regardless of order: C(5,2)=5×42×1=10C(5,2) = \frac{5 \times 4}{2 \times 1} = 10.

Decision rule

Question phrasingUse
Arrange, rank, sequence, PIN orderPermutation
Choose, select, committee, handCombination

Pattern families

Easy — Small n compute directly

List or multiply descending factors: 5×4×35 \times 4 \times 3 for P(5,3)P(5,3). Divide by r!r! when order ignored.

Medium — Formula application

Plug into P(n,r)P(n,r) or C(n,r)C(n,r). Simplify factorials before multiplying large numbers.

Hard — Complement or restrictions

“At least one” → total minus “none.” Adjacent or fixed-position constraints may reduce to smaller permutation subproblem.

Worked mini-examples

Example 1 — Permutation.
P(4,2)=4×3=12P(4,2) = 4 \times 3 = 12.
Example 2 — Combination.
(62)=6×52=15\binom{6}{2} = \frac{6 \times 5}{2} = 15.
Example 3 — Compare.
3-letter code from {A,B,C,D} without repeat: P(4,3)=24P(4,3) = 24. Choose 3 letters unordered: (43)=4\binom{4}{3} = 4.
Example 4 — Committee.
Choose 3 from 7 people for roles-free committee: (73)=35\binom{7}{3} = 35.
Example 5 — Complement.
Choose at least one red from 3 red and 4 blue (choose 2 total): total (72)=21\binom{7}{2}=21 minus no red (42)=6\binom{4}{2}=6 → 15.

Traps

  • Using combination when order matters (rankings, passwords).
  • Using permutation when order irrelevant (teams, subsets).
  • Forgetting to divide by r!r! when converting ordered to unordered.
  • C(n,r)=C(n,nr)C(n,r) = C(n, n-r) symmetry — useful check.
  • Identical items need division beyond basic C(n,r)C(n,r) (not all distinct).

Diagnostic (try yourself)

  1. How many ways to arrange 3 distinct books on a shelf?
  2. How many 2-person committees from 6 people (order irrelevant)?
  3. Compute P(5,3)P(5,3) and C(5,3)C(5,3). Which is larger?
  4. Word problem: “President and VP from 8 candidates.” Permutation or combination? Count?
  5. (100)\binom{10}{0} equals what?
Document outline

Keep your place and jump directly to a heading.

Table of Contents
System Normal // Awaiting Context

Intelligence Hub

Navigate the knowledge graph to generate context. The Hub adapts dynamically to surface backlinks, related notes, and metadata insights.